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Answer:
The chemical shift (δ) for CHBr₃ proton = <u>6.88 ppm</u>
Explanation:
In NMR spectroscopy, Chemical shift (δ) is expressed in parts per million (ppm) and is given by the equation:
....equation (1)
Given: Observed frequency: ν₁ = 2065 Hz,
Spectrometer frequency: ν'₁ = 300 MHz, ν'₂ = 200 MHz
To calculate the chemical shift (δ) for the given CHBr₃ proton, we use the equation (1)

Since in NMR spectroscopy, chemical shift is a <em>field independent scaling</em>. Thus the value of the chemical shift of a given proton, such as CHBr₃ proton, is <u><em>independent of the magnetic field strength of the spectrometer.</em></u>
<u>So the value of chemical shift of a given proton remains same when measured with a 300 MHz and 200 MHz NMR spectrometer.</u>
<u>Therefore, the chemical shift (δ) for CHBr₃ proton = 6.88 ppm</u>
The conclusion that you can draw about the electron
transitions that can take place for a magnesium atom is that the photons produced
are not of a lone wavelength, therefore from many dissimilar levels to
subsequent levels, with many different wavelengths joining to create white.
Changing states of matter would be a physical change
Answer: c
Explanation:
Chemical element, please if you now the answers of my two last questions help me