The atmospheric conditions at a particular time.
i did the test.
The heat needed to raise the temperature of 50g of substance by 15 c is calculated as follows
Heat = mc delta T
m= mass (50g)
c= specific heat capacity (0.92)
delta T= change in temperature( 15 c)
heat is therefore= 50 x 0.92 x 15 = 690
Nb: my answer has no units since the given specific heat capacity has no units
Answer:
f = 1.1041 × 10¹⁵ s⁻¹
λ = 2.72 × 10⁻⁷ m
Explanation:
Given data:
Energy of photon = 7.32 × 10⁻¹⁹ J
Wavelength = ?
Frequency = ?
Solution:
Formula
E = h. f
h = planck's constant = 6.63 × 10⁻³⁴ Kg.m²/s
Now we will put the values in equation
f = E/h
Kg.m²/s² = j
f = 7.32 × 10⁻¹⁹ Kg.m²/s² / 6.63 × 10⁻³⁴ Kg.m²/s
f = 1.1041 × 10¹⁵ s⁻¹
Wavelength of photon.
E = h.c /λ
λ = h. c / E
λ = (6.63 × 10⁻³⁴ Kg.m²/s × 3 × 10⁸ m/s) / 7.32 × 10⁻¹⁹ Kg.m²/s²
λ = 19.89 × 10⁻²⁶ / 7.32 × 10⁻¹⁹ m
λ = 2.72 × 10⁻⁷ m
