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IRISSAK [1]
3 years ago
10

If f(1) = 7 and f(n) = 5(n-1) + 2, then f(4) =

Mathematics
1 answer:
Igoryamba3 years ago
4 0

Answer:

17

Step-by-step explanation:

f(n)=5(n-1)+2

f(4)=5(4-1)+2

=5×3+2

=17

hope it helps

plz. mark as brainliest

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Ms. Gonzalez borrowed $4,500 from her bank to buy a jet ski. The loan has an 8.5% annual simple interest rate. If it takes Ms. G
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For the function f(x)=(1/2)⋅6^x , identify the domain, range, y-intercept, and asymptote.
skelet666 [1.2K]

Answer:

Step-by-step explanation:

f(x) = (1/2) *6^x = 2^-1 * 2^x *3^x

y= 2^ (x-1) * 3^x

Domain represents all values that x can have and is all real numbers

Range all values that y can have and is y > 0 ( all real numbers that are positive)

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6 0
3 years ago
Find all the zeros of the equation<br> -3x^4 + 27x^2 + 1200 = 0
guajiro [1.7K]

Answer:

\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i

Step-by-step explanation:

Biquadratic Equation

It's a fourth-degree equation where the terms of degree 1 and 3 are missing. It can be solved for the variable squared as if it was a second-degree equation, and then take the square root of the results

Our equation is

\displaystyle -3x^4+27x^2+1200=0

If we call y=x^2, our equation becomes a second-degree equation

\displaystyle -3y^2+27y+1200=0

Dividing by -3

\displaystyle y^2-9y-400=0

Factoring

\displaystyle (y-25)(y+16)=0

It leads to these solutions

\displaystyle y=25\ ,\ y=-16

Taking back the change of variable, we have for the first solution

\displaystyle x^2=25\Rightarrow x=-5,x=5

Now for the second solution, we get imaginary (complex) values

\displaystyle x^2=-16\Rightarrow x=4i,\ x=-4i

Summarizing, the four solutions for x are

\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i

5 0
3 years ago
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