The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Answer:
SSA (SIDE, ANGLE, SIDE)
Step-by-step explanation:
Hi!
Let's put the values in the equation.
10 · 5 + 16 ÷ 4 = ?
Using PEMDAS...
Multiplication
50 + 16 ÷ 4 = ?
Division
50 + 4 = ?
Addition
54
The answer is 54
Hope this helps! :)
Answer:
C. 6a + 5b
Step-by-step explanation:
36a^2-25b^2
Rewriting as
(6a)^2 - (5b)^2
We know this is the difference of squares
(x^2 -y^2) = (x-y)(x+y)
(6a - 5b) (6a+5b)
Answer: $40
Step-by-step explanation:
To find the whole number you divide the part by the percentage
so here it was 32/0.8
hope it helps
