Answer:
y=2e^(−x)cosx−e^(−x)sinx
Satisfies the equation
Step-by-step explanation:
Answer:
y=2e^(−x)cosx−e^(−x)sinx
y = e^(-x)[2cosx - sinx]
y': product law
y' = -e^(-x)[2cosx - sinx] + e^(-x)[-2sinx - cosx]
y' = -e^(-x)[2cosx - sinx + 2sinx + cosx]
y' = -e^(-x)[3cosx + sinx]
y" = e^(-x)[3cosx + sinx] - e^(-x)[-3sinx + cosx]
y" = e^(-x)[3cosx - cosx + sinx + 3sinx]
y" = e^(-x)[2cosx + 4sinx]
y" + 2y' + 2y
e^(-x)[2cosx + 4sinx] - 2e^(-x)[3cosx + sinx] +2e^(-x)[2cosx - sinx]
e^(-x)[4sinx - 2sinx - 2sinx + 2cosx - 6 cosx + 4cosx]
= e^(-x) × 0
= 0
Answer:
0.1 or 1/10
Step-by-step explanation:
The digits 4, 5, 6, 7 and 8 are randomly arranged to form a three digit number, where the digits are not repeated.
This is question of permutation.
Imagine this sum as; there are 3 boxes(blank spaces for digits) and 5 different fruits(digits) are to be put in these boxes, where a box can hold a maximum of only 1 fruit. The number of such permutations are: ⁵P₃
By formula (a! is factorial a):
ᵃPₙ
⁵P₃
⁵P₃
⁵P₃
⁵P₃= 60
This is the total count of possible numbers that can be formed.
Now, for a number to be greater than 800 and even; first digit should necessarily be 8. Last digit can be 4 or 6. Using these conditions, there are 6 possibilities. 854, 864, 874, 846, 856, 876 are the numbers.
The probability that number is even and greater than 800 is:
Answer:
(3, 3 )
Step-by-step explanation:
Under a translation < 2, 6 > , then
A(-5, - 3 ) → A'(- 5 + 2, - 3 + 6 ) → A'(- 3, 3 )
The line with equation x = 0 is the y- axis
Under a reflection in the y- axis
a point (x, y ) → (- x, y ), thus
A'(- 3, 3 ) → A''(3, 3 )