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lord [1]
4 years ago
9

A(-1,2)B(-7,4) find the midpoint of AB

Mathematics
2 answers:
sweet-ann [11.9K]4 years ago
8 0
You can find the mid point of the two by adding both the x's then divid by 2 and add both the y's and divide by 2 for example.

-1+(-7) =-8
-8/2 =-4
x= -4

2+4 = 6
6/2 =3
y=3

So the mid point is (-4,3) 
Zigmanuir [339]4 years ago
7 0
The midpoint would be (-4,3)
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almond37 [142]
4 of 9

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(sorry, not sure how to get bar notation for that)
3 0
3 years ago
Identify the similar triangles them find the x
Alex Ar [27]

Answer:

ADB and ABC are similar

x = 8

Step-by-step explanation:

hypotenuse in ADB = \sqrt{4^2 + 2^2 } = \sqrt{20}

since two triangles are similar,

\frac{2+x}{\sqrt{20} } = \frac{\sqrt{20}}{2}

solving for x, x=8

4 0
3 years ago
8. Which graph below shows the rule: output = 2 times input? (1 point)
madam [21]
Answer is the 3rd picture

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8 0
4 years ago
Read 2 more answers
The function f(x) = { x + 1 is used to complete this Which statements are true of the given function? Check all that apply. tabl
Dmitry [639]

Answer:

Options (1) and (5)

Step-by-step explanation:

Expression that defines the function is,

f(x)=\frac{1}{2}x+\frac{3}{2}

Option 1

f(-\frac{1}{2})=\frac{1}{2}(-\frac{1}{2})+\frac{3}{2}

          =-\frac{1}{4}+\frac{3}{2}

          =-\frac{1}{4}+1+\frac{1}{2}

          =1+\frac{1}{4}

          =1\frac{1}{4}

So, f(-\frac{1}{2} )=-2 is false.

Option 2

f(0) = \frac{1}{2}(0)+\frac{3}{2}

     = \frac{3}{2}

True.

Option 3

f(1) = \frac{1}{2}(1)+\frac{3}{2}

    = \frac{3+1}{2}

    = 2

Therefore, f(1) = -1 is false.

Option 4

f(2)=\frac{1}{2}(2)+\frac{3}{2}

       =1+1+\frac{1}{2}

       =2\frac{1}{2}

Therefore, f(2) = 1 is false.

Option 5

f(4) =\frac{1}{2}(4)+\frac{3}{2}

     =2+\frac{3}{2}

     =\frac{4+3}{2}

     =\frac{7}{2}

True.

Options (1) and (5) are the correct options.

5 0
3 years ago
My grade is a 77%, if i get a 0% on a paper worth 30% of my grade, what will my grade be now??
blsea [12.9K]
Grade=Paper+Other
Grade=(Grade_{paper}\times Value_{paper})+(Grade_{other}\times Value_{other})
Grade=(0 \times 30\%)+(77\% \times (1-30\%))
Grade=(0 \times 30\%)+(77\% \times 70\%)
Grade=0+53.9\%
Grade=53.9\%
6 0
4 years ago
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