The first choice can be any one of the 8 side dishes.
For each of these . . .
The 2nd choice can be any one of the remaining 7.
Total number of ways to pick 2 out of 8 = (8 x 7) = 56 ways .
BUT ...
That doesn't mean you can get 56 different sets of 2 side dishes.
For each different pair, there are 2 ways to choose them . . .
(first A then B), and (first B then A). Either way, you wind up with (A and B).
So yes, there are 56 different 'WAYS' to choose 2 out of 8.
But there are only 28 different possible results, and 2 'ways'
to get each result.
Answer:
The correct answer would be chart A.
Step-by-step explanation:
I say symmetric. Both variables are the same, and the equation is showing their equality. This is my best guess.
Hope this helps!
Hi this is my BFF can u tell him to have a nice day thx
Area of triangle: 1/2(base)(height)
Area of rectangle: length × width
Find the area of the triangles on the sides first using 1/2(base)(height).
Plug 8 for the base and 6 for the height.
1/2(8)(6) = 24 units²
Multiply 24 by 2 for both of the triangles.
(24)(2) = 48 units²
Find the area of the rectangles of the object using length × width.
For the rectangle on top, you can find the width using the Pythagorean Theorem: a² + b² = c².
Plug in 6 and 8 for a and b, and find c (width).
6² + 8² = c²
36 + 64 = 100
Square root both sides; √100 = 10.
The width of the rectangle on top is 10.
Now plug 20 for the length and 10 for the width.
20 × 10 = 200 units²
For the rectangle on the bottom, plug in 20 for the length and 8 for the width.
20 × 8 = 160 units²
For the rectangle on the side, plug in 20 for the length and 6 for the width.
20 × 6 = 120 units²
Add up all the areas ⇒ 48 + 200 + 160 + 120 = 528 units².
