All categories

2 years ago

Write an equation in slope y-intercept form A(2,6),m=0

Mathematics

1 answer:

REY [17]2 years ago

3 0

Solve for b:

y = 0x + b

6 = 0 + b

b = 6

The answer is y = 0x + 6

You might be interested in

Which expression is equivalent to -2( x-7 )?

AnnyKZ [126]

Answer: -2x+14

Step-by-step explanation: use the distributive property. -2 times x and -2 times -7. -2x+14

5 0

1 year ago

Read 2 more answers

How do I choose a method to find the product

Mrrafil [7]

What do you mean?
It's ok.
here's an example of product..
3 X 5 = 15.

7 0

2 years ago

Find the area of the shaded region.

kolbaska11 [484]

Answer:

$\boxed{ \tt\longrightarrow \: Area \: Of \: Shaded \: region \: =\boxed{ \tt 39 \: in²}}$

Step-by-step explanation:

Given:

The Dimensions of Parallelogram are 12 in.(Base) and 7 in.(Height)

And,

The Dimensions of Rectangle are 9 in.(Length) and 5 in.(Breadth).

To Find:

The Area of Shaded region

Solution:

When the dimensions of parallelogram and the dimensions of rectangle are given, we need to find the Shaded region using this formula:

$\boxed{\tt \longrightarrow Area = (Parallelogram - Rectangle)}$

We know that the formula of Parallelogram is base*height[b×h] and the formula of rectangle is length*breadth[l*b] .

$\tt\longrightarrow \: Area =B×h-l×b$

Put their values accordingly:

$\longrightarrow \tt Area = (12 \times 7 - 9 \times 5)in {}^{2}$

Simplify it.

[Follow BODMAS Rule strictly while simplifying]

$\tt\longrightarrow \: Area = (84 - 45 ) in {}^{2}$

$\tt\longrightarrow \: Area = 39 \: {in}^{2}$

Hence, the Area of Shaded region would be 39 in² or 39 sq. in. .

$\rule{225pt}{2pt}$

I hope this helps!

8 0

1 year ago

Read 2 more answers

Two lines, A and B, are represented by the equations given below!

lara [203]

Answer:

The solutions to the system of equations are:

$y=-8,\:x=-4$

Thus, option C is true because the point satisfies BOTH equations.

Step-by-step explanation:

Given the system of the equations

$\begin{bmatrix}y=x-4\\ y=3x+4\end{bmatrix}$

Arrange equation variables for elimination

$\begin{bmatrix}y-x=-4\\ y-3x=4\end{bmatrix}$

$y-3x=4$

$-$

$\underline{y-x=-4}$

$-2x=8$

$\begin{bmatrix}y-x=-4\\ -2x=8\end{bmatrix}$

solve for x

$-2x=8$

Divide both sides by -2

$\frac{-2x}{-2}=\frac{8}{-2}$

$x=-4$

$\mathrm{For\:}y-x=-4\mathrm{\:plug\:in\:}x=-4$

$y-\left(-4\right)=-4$

$y+4=-4$

$y=-8$

The solutions to the system of equations are:

$y=-8,\:x=-4$

Thus, option C is true because the point satisfies BOTH equations.

8 0

2 years ago

Solve the exponential equation: 3^2– ^x = 1

Flura [38]

$x = 2$

c.) x=2

<h2>hope it helps!</h2>

5 0

2 years ago