The answer is .
Multiple numerators by nums, and denoms by denoms.
· =
simplified is
Hope this helped and branluest would be appreciated
<span>2/5g+3h-6 when g=10 and h=6
</span><span>2/5 (10) +3(6) - 6
</span><span>= 4 + 18 - 6
= 16
</span>
Answer:
Option B.
Step-by-step explanation:
The given inequalities are
We need to find the ordered pair which makes both inequalities true.
Check the above inequalities for each given ordered pair.
For (-3,5),
(False)
For (-2,2),
(True)
(True)
So, both inequalities are true for (-2,2). Option B is correct.
For (-1,-3),
(False)
For (0,-1),
(False)
Both inequalities are not true for (-3,5), (-1,-3) and (0,-1).
Therefore, the correct option is B.
Answer:
4 /15
Step-by-step explanation:
From the number cube :
Count of Numbers greater than 4 = 16
Sample space of number cube = 20
P(number greater than 4) = 16 / 20 = 4/5
Word : ATTENTION
Count of letters in attention = 9
Count of T's in attention = 3
P(choosing T) = 3 / 9 = 1/3
P(greater than 4, then T) = 4/5 * 1/3 = 4 /15
Answer:
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