A bearing of 34° corresponds to corresponding angle of θ=90-34=56°
The (x,y) values for the position of the ship after completing its first heading are:
x=(10.4cos 56)
y=(10.4sin56)
The trigonometric angle for θ=90-90=0
The (x,y) values for the postion of the ship after completing the second bearing is:
x=(10.4 cos56)+(4.6cos0)≈10.4 mi
y=(10.4sin56)+(4.6sin0)≈8.6mi
the distance from the port will therefore be:
d=√(10.4²+8.6²)≈13.5 miles
It trigonometric angles is:
θ=arctan(y/x)
θ=arctan(8.6/10.4)
θ≈39.6°
Thus the bearing angle is:
90-39.6=50.4°
A^3=343 in^3
take the cubic root
a=7
Perimeter= 7in+7in+7in+7in=28inch
Answer:
$36.05
Step-by-step explanation:
Do 216.30 then divide that by 6. With that you get 36.05; the amount she makes per hour.
2 - 6 ÷ 6 (Order of Operations - PEMDAS)
= 2 - 1
= 1
Answer is 1
...........................
