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Grace [21]
2 years ago
10

Both physical and social systems can be natural or human-made. true or false

Mathematics
1 answer:
Ahat [919]2 years ago
8 0
I’m answering for so false
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Simplify: (10x + 6) + (2x − 9).
erastovalidia [21]

Answer:

<h2>12x−3</h2>

Step-by-step explanation:

Let's simplify step-by-step.

10x+6+2x−9

=10x+6+2x+−9

Combine Like Terms:

=10x+6+2x+−9

=(10x+2x)+(6+−9)

=12x+−3

Answer:

=12x−3

<h3><u>Brainliest Please!</u></h3>
8 0
3 years ago
Rhonda sold five appliances this week. She sold a stove for $800.00, a refrigerator for $1,250.00, a microwave for $120.00, a di
VikaD [51]

whatever% of anything is just (whatever/100) * anything.


800+1250+120+625+65 gives us 2860.

now, she doesn't get any commission from the 2000, just the surplus, the 860.

how much is 15% of 860? well is just (15/100) * 860.

8 0
3 years ago
Read 2 more answers
For which values of P and Q does the following equation have infinitely many solutions? Px-37=Qx-37
Lyrx [107]

Answer:

The equation has infinitely many solutions for any value of P and Q such that P=Q.

Step-by-step explanation:

Px - 37 = Qx - 37

Px - Qx - 37 = -37

x (P-Q) = 0

==> P-Q=0 ==> P=Q


4 0
3 years ago
At carl's combine diner, there are three size of coffee drinks regular (300ml), large (500ml) and extra large (800mL), and they
MariettaO [177]

Answer:

The number of regular, large, and extra-large drinks are 12, 15, and 10 respectively.

Step-by-step explanation:

Given that the cost for regular coffee drinks (300 ml)=$2.25

The cost for large coffee drinks (500 ml)=$3.25

The cost for extra large coffee drinks (800 ml)=$5.75

Let p,q, and r be the number of regular, large, and extra-large coffee sold.

As the diner sold a total of 37 coffees, so

p+q+r=37

r=37-p-q...(i)

The volume of p regular coffee = 300p ml

The volume of q  large coffee = 500q ml

The volume of r extra-large coffee = 800r ml

As the total volume of coffee sold was 19,100mi, so

300p+500q+800r=19100

By using equation (i)

300p+500q+800(37-p-q)=19100

300p+500q+800 x 37 - 800p - 800q=19100

-500p-300q=19100-29600

500p+300q=10500

500p=10500-300q

p=21-0.6q...(ii)

Now, the cost of p regular coffee=$2.25p

The cost of q large coffee=$3.25q

The cost of r extra-large coffee=$5.75r

As the amount of money made in coffee sales was $133.25, so

2.25p+3.25q+5.75r=133.25

By using equations (1)  we have

2.25p+3.25q+5.75(37-p-q)=133.25

2.25p+3.25q+212.75-5.75p-5.75q=133.25

3.50p+2.50q=79.5

From equation (ii)

3.5(21-0.6q)+2.50q=79.5

73.5-2.1q+2.5q=79.5

0.4q=79.5-73.5=6

q=6/0.4

q=15

From equation (ii)

p=21-0.6(15)

p=12

From equation (i)

r= 37-12-15

r=10

Hence, the number of regular, large, and extra-large drinks are 12, 15, and 10 respectively.

5 0
3 years ago
Find the length of side x in simplest radical form with a rational denominator.<br> X
scoundrel [369]
This question is gonna need the picture to go with it
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2 years ago
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