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ipn [44]
3 years ago
12

4 times a number plus 4 is twice the number​

Mathematics
1 answer:
nekit [7.7K]3 years ago
7 0

Answer:

idk go back to 5th grade you might learn how to add but for ur answer is 8

Step-by-step explanation:

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Y>3 is the correct answer because more than 3 inches of rain fell.
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3 years ago
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Petra jogs 5 miles in 40 minutes. At this rate, how long would it take her to jog 7 miles? Petra would take minutes to jog 7 mil
tatuchka [14]

Answer:

the answer would be 56 minutes.

Step-by-step explanation:

7 x 40 = 280

5n = 280

n = 56

3 0
3 years ago
(3 + 8i) + (7 -- 2i) - (6 - 5i)<br> AO 4+1<br> B.O4 + 117<br> c. 16 +1<br> D.O4 + 1143
Lubov Fominskaja [6]

Answer: (3 + 8i) + (7 -- 2i) - (6 - 5i) = 4 + 15i

_____________________________________________

Simplify the expression.

4 + 15i

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3 0
2 years ago
Combine like terms to simplify the expression:<br><br> 2/5k-3/5+1/10k
charle [14.2K]

Answer:

1/2k-3/5

Step-by-step explanation:

8 0
3 years ago
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A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p
Alekssandra [29.7K]

Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so z = 1.645.

Item a:

The estimate is \pi = 0.213 - 0.195 = 0.018.

The sample size is <u>n for which M = 0.03</u>, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}

\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2

n = 53.1

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence \pi = 0.05

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 751.7

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

5 0
2 years ago
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