First, you set your problem up like this:
-4x+3=2x-6
add 6 to both sides so it looks like this:
-4x+9=2x
add 4x to both sides so it looks like this:
9=6x
divide 6 from both sides so this is your answer:
1.5=x
Answer:
1, 1.5, -1 1/5
Step-by-step explanation:
D. Because the teachers are what matter in this survey.
so we know the terminal point is at (9, -3), now, let's notice that's the IV Quadrant
![\bf (\stackrel{x}{9}~~,~~\stackrel{y}{-3})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{9^2+(-3)^2}\implies c=\sqrt{81+9}\implies c=\sqrt{90} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx%7D%7B9%7D~~%2C~~%5Cstackrel%7By%7D%7B-3%7D%29%5Cimpliedby%20%5Ctextit%7Blet%27s%20find%20the%20%5Cunderline%7Bhypotenuse%7D%7D%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20c%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3Dhypotenuse%5C%5C%20a%3Dadjacent%5C%5C%20b%3Dopposite%5C%5C%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20c%3D%5Csqrt%7B9%5E2%2B%28-3%29%5E2%7D%5Cimplies%20c%3D%5Csqrt%7B81%2B9%7D%5Cimplies%20c%3D%5Csqrt%7B90%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
The human body has about 5.5 liters of blood
3 deciliters is about 0.3 liters
so 5.5/0.3=18.33333
so she could fill 18 and 1/3 glasses before she died
wait
oooooh, she has a supply of blood other than her own, nvm, I should read better
1 decileter is 1/10 of a liter
so 3/10 of a liter per glass
6 of those 2 liter bottles
so total is 6*2=12 liters
so
3/10 times number of glasses=12
times both sides by 10/3
number of glasses=120/3
number of glasses=40
can fill 40 glasses with the blood she is supplied (not including her own)
