The probability of winning exactly 21 times is 0.14 when the probability of winning the arcade game is 0.659.
We know that binomial probability is given by:
Probability (P) = ⁿCₓ (probability of 1st)ˣ x (1 - probability of 1st)ⁿ⁻ˣ
We are given that:
Probability of winning on an arcade game = P(A) = 0.659
So, the Probability of loosing on an arcade game will be = P'(A) = 1 - 0.659 = 0.341
Number of times the game is being played = 30
We have to find the Probability of winning exactly 21 times.
Here,
n = 30
x = 21
P(A) = 0.659
P'(A) = 0.341
Using the binomial probability formula, we get that:
Probability of winning exactly 21 times :
P(21 times) = ³⁰C₂₁ (0.659)²¹ x (0.341)⁷
P( 21 times ) = 0.14
Therefore, the probability of winning exactly 21 times is 0.14
Learn more about " Binomial Probability " here: brainly.com/question/12474772
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Answer:
The answer would be A.
Step-by-step explanation:
Sorry if the answer is wrong.
Answer:
step 1: you subtract 28 and 3 to get 5x by itself
step 2:divide 25 and 5 to solve or x
step 3: x equals 5
Step-by-step explanation:
Answer:
The answer to this question can be defined as follows:
i) 
ii) x=22 units
iii) Maximum profit: 953.45
Step-by-step explanation:
Given value:
p(x) = 211 − 5x \\
C(x) = 1,401 + 16x
The formula for calculating the profit function value:
The formula for calculating the value for maximum profit:
So, the production level is 22 units
Maximum profit:
