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3 years ago

I WILL MAKE YOU BRAINLIEST!!

1 answer:

4 0

Part A:The original brand was 12$ each and the new one is 8$ each.
12-8=4
Part B:she will save 16$ each month because y=12*4 and y=8*4 is 16$

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Find the 15th term of the arithmetic sequence x + 3, – X – 1, -3x – 5,...

tatuchka [14]

Answer:

-53-27x

Step-by-step explanation:

Answer attached...

Hope it helps :)

5 0

3 years ago

Find the equation of the line passing through the point (4,−1) that is parallel to the line 2x−3y=9.

motikmotik

Hey there!

Line passes through (4, -1) & is parallel to 2x -3y=9

Let's start off by identifying what our slope is. In the slope-intercept form y=mx+b, we know that "m" is our slope.

The given equation needs to be converted into slope-intercept form and we can do this by getting y onto its own side of the equal sign.

Start off by subtracting 2x from both sides.

-3y = -2x + 9

Then, divide both sides by -3.

y = (-2x + 9)/-3

Simplify.

y = 2/3x - 3

"M" is simply a place mat so if we look at our given line, the "m" value is 2/3. Therefore, our slope is 2/3.

We should also note that we're looking for a line that's parallel to the given one. This means that our new line has the same slope as our given line. Therefore, our new line has a slope of 2/3.

Now, we use point-slope form ( y-y₁=m(x-x₁) ) to complete our task of finding a line that passes through (4, -1). Our new slope is 2/3 & it passes through (4, -1).

y-y₁=m(x-x₁)

Let's start by plugging in 2/3 for m (our new slope), 4 for x1 and -1 for y1.

y - (-1) = 2/3(x - 4)

Simplify.

y + 1 = 2/3 + 8/3

Simplify by subtracting 1 from both sides.

y = 2/3x + 8/3 - 1

Simplify.

y = 2/3x + 5/3

~Hope I helped!~

7 0

4 years ago

Let , −5−6 be a point on the terminal side of θ . find the exact values of cosθ , cscθ , and tanθ .

gizmo_the_mogwai [7]

Given that point (-5, -6) is a point on the terminal side of θ. Since both the x coordinate and the y-coordinate are negative, θ is in the third quadrant.

The side opposite θ is -6 and the side adjacent θ is -5.

The hypothenus is given by $\sqrt{(-6)^+(-5)^2}=\sqrt{36+25}=\sqrt{61}$

The exact value of cosθ is given by:

$\cos\theta= \frac{adjacent}{hypothenuse} = \frac{-5}{\sqrt{61}}$

The exact value of cscθ is given by:

$\csc\theta= \frac{hypothenuse}{opposite} = \frac{\sqrt{61}}{-6}$ 

The exact value of tanθ is given by:

$\tan\theta= \frac{opposite}{adjacent} = \frac{-6}{-5} =1.2$

5 0

4 years ago

Do 5cm 5cm 10cm form a triangle?

EastWind [94]

Yes! that would be an isosceles triangle.

5 0

3 years ago

Read 2 more answers

You are investing towards your future. You deposit $18,000 into an account that

mojhsa [17]

Answer:

=20250