Find the 15th term of the arithmetic sequence x + 3, – X – 1, -3x – 5,...
1 answer:
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- + 6
divide each term on the numerator by 7b
= - 7 / 7b + 42
/ 7b
= - + 6
The answer you are looking for is .
Explanation:
4(4x−8)+4(3x−7)=7(2x+5)+6
Step 1: Simplify both sides of the equation.
4(4x−8)+4(3x−7)=7(2x+5)+6
(4)(4x)+(4)(−8)+(4)(3x)+(4)(−7)=(7)(2x)+(7)(5)+6(Distribute)
16x+−32+12x+−28=14x+35+6
(16x+12x)+(−32+−28)=(14x)+(35+6)(Combine Like Terms)
28x+−60=14x+41
28x−60=14x+41
Step 2: Subtract 14x from both sides.
28x−60−14x=14x+41−14x
14x−60=41
Step 3: Add 60 to both sides.
14x−60+60=41+60
14x=101
Step 4: Divide both sides by 14.
14x
14
=
101
14
x=
101
14