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3 years ago

What is the answer to this question?

Mathematics

1 answer:

Serga [27]3 years ago

6 0

Answer: 87.5

Step-by-step explanation:

The Area formula for a Trapezium is

depicted in the two picture below.

As seen in the picture Area equals

A+B(h) all divided by 1/2 or simplistic terms 2.

A+b

A= ---------- (h)

So we need to plug our information in

as Depicted in the picture measurement A is first top side

And B is bottom base

so h IS the height of the figure. Its the middle line in the middle of the figure.

10+15

A= ________(7)

10+15=25

25*7=175

175/2=87.5

So your answer is

Area of ABCD is 87.5

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How do you find a vector that is orthogonal to 5i + 12j ?

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$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\$

$\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
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\\\\\\
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if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

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\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}
\\\\\\
\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}$

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3 years ago

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