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ozzi
3 years ago
5

Help..........................

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0

since all of the sides are not equal, it is not a regular polygon.

a regular polygon is when all of the sides are equal, and the same with the angles.

hope this helps you!! <3

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PLEASE HELP ME!!!!!!! I think the answer is exponential but I am not 100% sure!!!!!!!
babunello [35]
It is exponentially each time you are dividing by 4/3
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The first thing you should do in solving a word problem is estimate what you think the answer would be.
Lelu [443]

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The answer is True.

Step-by-step explanation:

  • <u>Estimate the Answer Before Solving Having a general idea of a ballpark answer .</u>
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2 years ago
Find a formula for the general term an of the sequence, assuming that the pattern of the first few terms continues. (assume that
Lilit [14]
Your sequence
  -8, 16/3, -32/9, 64/27
is a geometric sequence with first term -8 and common ratio
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6 0
3 years ago
what is the perimeter measured in centimeters of the rectangle pictured below do not include units in your answer
Snezhnost [94]

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7 0
2 years ago
WHAT IS THE REMAINDER WHEN <img src="https://tex.z-dn.net/?f=32%5E%7B37%5E%7B32%7D%20%7D" id="TexFormula1" title="32^{37^{32} }"
Feliz [49]

Recall Euler's theorem: if \gcd(a,n) = 1, then

a^{\phi(n)} \equiv 1 \pmod n

where \phi is Euler's totient function.

We have \gcd(9,32) = 1 - in fact, \gcd(9,32^k)=1 for any k\in\Bbb N since 9=3^2 and 32=2^5 share no common divisors - as well as \phi(9) = 6.

Now,

37^{32} = (1 + 36)^{32} \\\\ ~~~~~~~~ = 1 + 36c_1 + 36^2c_2 + 36^3c_3+\cdots+36^{32}c_{32} \\\\ ~~~~~~~~ = 1 + 6 \left(6c_1 + 6^3c_2 + 6^5c_3 + \cdots + 6^{63}c_{32}\right) \\\\ \implies 32^{37^{32}} = 32^{1 + 6(\cdots)} =  32\cdot\left(32^{(\cdots)}\right)^6

where the c_i are positive integer coefficients from the binomial expansion. By Euler's theorem,

\left(32^{(\cdots)\right)^6 \equiv 1 \pmod9

so that

32^{37^{32}} \equiv 32\cdot1 \equiv \boxed{5} \pmod9

7 0
2 years ago
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