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4 years ago

PLEASE NOTIFY IF IF 52-55 are TRUE OR FALSE I BEGGG

Mathematics

1 answer:

azamat4 years ago

6 0

52, false 55 false all intergers are whole numbers

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NEED ANSWER ASAP THE TEST IS TIMED!!!!!!!

frosja888 [35]

Answer:

5/-1

Step-by-step explanation:

y1-y2/x1-x2

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3 years ago

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Sensei Umeh’s ""Active Hands"" karate program grew from 8 members to 15 last week. What is the percent of change?

Tom [10]

Answer:

187.5% increase

Step-by-step explanation:

Percent change formula: $\frac{x_{2}-x_{1}}{x_{1}}$

Initially, the program had 8 members and ended with 15 so $\frac{15-8}{8}=\frac{7}{8}=0.875=87.5$

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3 years ago

Robert planted 18 daffodil bulbs and 24 tulip bulbs in his garden last winter. If all the bulbs sprout and bloom this spring, wh

-BARSIC- [3]

It's 4:3 because if its 24:18 you can break it down by dividing 6 from both of them to get 4:3

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3 years ago

When the outliers are removed, how does the mean change?

vagabundo [1.1K]

Answer:

The mean increases by 3.

Step-by-step explanation:

What's an outlier?

An outlier is a data point that's very different from the other data points. In this example, the outlier is 50, as the other data points are around the number 80.

What's the mean of a data set?

The mean is the average of a data set. It's found by adding up all the numbers in the set and then dividing by the number of data points there is.

How do we solve this problem?

First, we find the mean of the data set with the outlier, 50.

$\frac{50+76+78+79+79+80+81+82+82+83}{10}$
$\frac{770}{10}$
$77$

Next, we find the mean of the set without the outlier.

$\frac{76+78+79+79+80+81+82+82+83}{9}$
$\frac{720}{9}$
$80$

Lastly, we subtract 77 from 80 to find the difference.

$80 - 77 = 3$

Therefore, the answer is The mean increases by 3.

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3 years ago

To solve the equation 2x - 6 = 14, first

BARSIC [14]

You would add 6, so you can divide both sides by 2 later on in the equation. Since it is subtracting six on one side of the equation you need to add on the other side to cancel it out.

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3 years ago

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