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2 years ago

Which strategy best explains how to solve this problem?

1 answer:

6 0

I think its A. I think it would be a good way to model it off chips. You can find that answer by putting one chip out for the first week, then you could keep adding chips twice the amount 5 more times, that should add up to six weeks. you should have your answer after that.

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Simplify the expression<br> –2 + 7(x + 8)

anastassius [24]

Answer:

54+7x

Step-by-step explanation:

-2+7(x+8)

-2+7x+56

54+7x

7 0

2 years ago

Read 2 more answers

Solve the two-step equation. -9x 0. 4 = 4 Which operation must be performed to move all the constants to the right side of the e

AlekseyPX

The steps needed to solve the given equation is required.

Adding the opposite value of the constant to both sides.

Divide both sides by the coefficient of the variable.

The solution to the equation is

The given equation is

In order to solve this we first move constants to the side opposite of the variable.

This is done by adding the opposite value of the constant to both sides.

Here is the constant so we add to both sides.

Now, we divide both sides by the coefficient of the variable.

The solution to the equation is

3 0

2 years ago

If f(x) = 7x − 1, what does f(12) represent?

olga2289 [7]

I think it is D, too. Did you submit the test yet?

8 0

2 years ago

Identify the quadratic function(s). (Select all that apply.)

Katen [24]

General Idea:

The quadratic function of the form $ax^2+bx+c=0$ .

Applying the concept:

Simplifying the equation in option A, we get...

$A) \; 8 - 5x = 4(3x - 1) \\Distributing \; 4 \; in \; right \; side \; of \; the \; equation. \\ \\ 8 - 5x = 12x - 4\\ The \; equation \; is \; a \; linear \; equation \; with \; variable \; on \; both \; sides.$

Simplifying the equation in option B, we get...

$B) \; \; (4a + 2)(2a - 1) + 1 = 0\\ Multiplying \; First \; \; Outer \; \; Inner \; \; Last \; terms\; in\; the \; left \; side.\\ \\ 4a \cdot 2a + 4a \cdot -1 + 2 \cdot 2a + 2 \cdot -1 + 1 = 0\\ \\ 8a^2-4a+4a-2+1=0\\ Combining \; like \; terms \; \\ \\ 8a^2 - 1 = 0\\ Above \; is \; a \; Quadratic \; Equation!$

Simplifying the equation in Option C, we get...

$C)\; \; 2y + 2(3y - 5) = 0\\ Distributing \; 2 \; in \; left \; side\\ \\ 2y+6y-10=0\\ Combining \; like \; terms\\ \\ 8y - 10 = 0\\ Above \; Equation \; is \; linear \; equation$

Simplifying the equation in Option D, we get

$D) \;2b(b - 7) + b = 0\\ Distributing \; 2b\; in \;the \;left\; side \;of \;the\;equation\\ \\ 2b \cdot b - 2b \cdot 7+b=0\\ Simplify \; in \; the \; left \; side \; of \; the \; equation\\ \\ 2b^2-14b+b=0\\ Combine \; like \; terms\\ \\ 2b^2-13b=0\\ Above \; equation \;is \;a \; Quadratic\;Equation!$

<u>Conclusion:</u>

Option B) & Option D) are quadratic equation!

7 0

2 years ago

Read 2 more answers

Solve for x. The polygons in each pair are similar.

Nonamiya [84]

If each is similar, then 6 times (5) = 30
therefore 8 times (5) = 6X - 8
40 = 6X - 8
add 8 to both sides 48 = 6X
divide by 6 8 = X

3 0

2 years ago