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Sav [38]
3 years ago
6

What is the equation of the line passing through the points (2, -1) and (5, -10) in slope-intercept form? O y=-3x-5 O y=-3x+5 O

Y= 3x-5 O y = 3x + 5​
Mathematics
1 answer:
Nimfa-mama [501]3 years ago
4 0

Answer:

y= -3x+5

Step-by-step explanation:

firstly find the gradient given by the formula

m=y2-y1/x2-x1

so in this case y2 is -10,x2 is 5,y1 is -1 and x1 is 2

m= -10+1/5-2

m= -9/3

= -3

after finding the gradient use the equation

y-y1=m( x-x1)

y+1= -3(x-2)

y+1= -3x+6

y= -3x+6-1

y= -3x+5

I hope this helps

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What is the perimeter of a polygon with verticals at (-1, 3) , (-1, 6) , (2, 10) , (5, 6) , and (5, 3)
Marat540 [252]

Answer:

22 units

Step-by-step explanation:

The perimeter of a polygon is said to be the sum of the length of it's sides.

From the question, we have 5 vertices. This means the polygon is a pentagon. It's given vertices are

A = (−1, 3)

B = (−1, 6) ​

C = (2, 10)

D = (5, 6) ​​

E = (5, 3) ​

To find the distance between two points, we use the formula

d = √[(y2 - y1)² + (x2 - x1)²]

Between A and B, we have

d(ab) = √[(6 - 3)² + (-1 --1)²]

d(ab) = √(3²) + 0

d(ab) = √9 = 3

Between B and C, we have

d(bc) = √[(10 - 6)² + (2 --1)²]

d(bc) = √[4² + 3²]

d(bc) = √(16 + 9) = √25 = 5

Between C and D, we have

d(cd) = √[(6 - 10)² + (5 - 2)²]

d(cd) = √[(-4)² + 3²]

d(cd) = √(16 + 9) = √25 = 5

Between D and E, we have

d(de) = √[(3 - 6)² + (5 - 5)²]

d(de) = √(-3)² + 0

d(de) = √9 = 3

Between E and A, we have

d(ea) = √[(3 - 3)² + (5 --1)²]

d(ea) = √[0 + (6)²]

d(ea) = √36 = 6

The perimeter is given as

d(ab) + d(bc) + d(cd) + d(de) + d(ea) =

3 + 5 + 5 + 3 + 6 = 22 units

7 0
2 years ago
Use f(x) =1/2 x and f^-1(x)=2x to solve the problems
MAXImum [283]
The answer to the question

4 0
3 years ago
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Paco solves the equation -3x-5=1
Levart [38]

Answer:

x= -2

Step-by-step explanation:

-3x-5=1

+5 on each side to balance the equation:

-3x=6

Divide by -3 on each side:

x=-2

7 0
3 years ago
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Which relation is a function of x?<br> 1 {(1,2), (7, 6), (3, 2), (1, 0), (5, 6)}. <br> 3. x=3y²–7
avanturin [10]

9514 1404 393

Answer:

  The given graph shows a function of x.

Step-by-step explanation:

Neither 1 nor 3 is a single-valued relation for some values of x. The graph shown passes the vertical line test, so does represent a function.

The graph is a relation that is a function of x.

___

The attached graph is of the equation of 3. A vertical line will intersect the graph in more than one place, so the relation is NOT a function.

4 0
2 years ago
How many F's can I get in order to still pass 7th grade??? What's the maximum??
guapka [62]
:D i hav th same question cuz i hav lik 3 E's
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