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Sav [38]
3 years ago
6

What is the equation of the line passing through the points (2, -1) and (5, -10) in slope-intercept form? O y=-3x-5 O y=-3x+5 O

Y= 3x-5 O y = 3x + 5​
Mathematics
1 answer:
Nimfa-mama [501]3 years ago
4 0

Answer:

y= -3x+5

Step-by-step explanation:

firstly find the gradient given by the formula

m=y2-y1/x2-x1

so in this case y2 is -10,x2 is 5,y1 is -1 and x1 is 2

m= -10+1/5-2

m= -9/3

= -3

after finding the gradient use the equation

y-y1=m( x-x1)

y+1= -3(x-2)

y+1= -3x+6

y= -3x+6-1

y= -3x+5

I hope this helps

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Step-by-step explanation:

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X-intercept and y-intercepts og y=x^2-3
Rufina [12.5K]

Answer:

Part 1) The y-intercept is the point (0,-3)

Part 2) The x-intercepts are the points (-\sqrt{3},0)\ and\ (\sqrt{3},0)

Step-by-step explanation:

we have

y=x^{2}-3

This is a vertical parabola open upward

step 1

Find the y-intercept

we know that

The y-intercept is the value of y when the value of x is equal to zero

so

For x=0

y=(0)^{2}-3

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The y-intercept is the point (0,-3)

step 2

Find the x-intercepts

we know that

The x-intercept is the value of x when the value of y is equal to zero

so

For y=0

x^{2}-3=0

solve for x

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x^{2}=3

take square root both sides

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so

The x-intercepts are the points (-\sqrt{3},0)\ and\ (\sqrt{3},0)

3 0
3 years ago
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Dima020 [189]

Answer:

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Step-by-step explanation:

x^2 – 12x

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