If it was one year it would be 2200 and you just keep adding 200 for each year.
Answer:
i belive p= 8
Step-by-step explanation:
10-2= 8
8+2 is 10 so p +2 woyld =10
Answer:
<em>1500(1.02)^x + 600x</em> is how much he has in savings at the end of x years where it be in the bank or elsewhere
Step-by-step explanation:
x is in years
Let's just think about the investment of 1500 in an account earning 2% per year.
Before the years even start, you are at 1500 ( present value).
The next year (year 1), it would be 1500*.02+1500=(1500)(1.02).
The next year (year 2), it would be 1500(1.02)(.02)+1500(1.02)=1500(1.02)(1.02).
We keep multiplying factors of (1.02) each time.
So for year x, you would have saved 1500(1.02)^x.
Now we are saving 50 cash per month. Per year this would be 12(50) since there are 12 months in a year. 12(50)=600.
So the first year you would have 600.
The second year you would have 600(2) or 1200.
The third year you would have 600(3) or 1800.
Let's put this together:
1500(1.02)^x + 600x
Answer:
9/6
Step-by-step explanation:
1/4 is less than 1, so its not 1. 5/9 is also less than 1, so its also not 1. 14 divided by 7 equals 2 so that is not 1. 9/6 is the only option left :)
