Check the picture below.
since the width is just a dimension unit, it can't be -31.
what is the length? well, the length is w + 30.
Answer:
-7 minus -2 = -5 (the last one)
Step-by-step explanation:
Thats the only one that made sense to me
Answer:
D. 4(2x² + 4x - 6); 130.0 inches
Step-by-step explanation:
Margot is sewing a ribbon on a seam along the perimeter of a square pillow. The side length of the pillow is 2x²+1 inches. She plans to make a similar pillow, including the ribbon, whose side length is 4x−7 inches. What expression can be used for the length of ribbon that she needs for both pillows, and what is the length if x = 3.5?
2x2+4x−6; 22.0 inches
2x2+4x−6; 32.5 inches
4(2x2+4x−6;) 88.0 inches
4(2x2+4x−6;) 130.0 inches
Perimeter of a square = 4 * side length
1- First square pillow
length = 2x²+1 in
Perimeter of first pillow = 4 * (2x²+1) in
Second square pillow
length = 4x-7 in
Perimeter of second pillow = 4(4x-7) in
Total ribbon length required = perimeter of first square pillow + perimeter of second square pillow
Total ribbon length required = 4(2x²+1) + 4(4x-7)
Factorise
4 is the common factor
=4(2x²+1)+(4x-7)
=4(2x²+1+4x-7)
=4(2x²+4x-6)
Total ribbon length required=4(2x²+4x-6)
If x=3.5
Total ribbon length required=4(2x²+4x-6)
=4{2(3.5)²+4(3.5)-6}
=4{2(12.25)+14-6)
=4(24.5+14-6)
=4(32.5)
=130.0 inches
Answer:
2 hours
Step-by-step explanation:
For if you start at 1 hour you end up with one bus 45 miles away from the school and the other 40 miles. If you then add these then you find out how far apart they are which is 85 at this point and time. If you do another hour the bus going 45 is now 90 miles away from the school. The other one will be 80. After you add these two number to find how far apart they are you end up with 170.
