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Wittaler [7]
3 years ago
10

I need help answering this question for trig equations. Sec^2x+4secx=-4

Mathematics
1 answer:
aliina [53]3 years ago
3 0

Answer:

x = 120°

Step-by-step explanation:

We are given;

sec²x + 4secx = -4

Rearranging gives;

sec²x + 4secx + 4 = 0

Factorizing the left hand side gives;

(sec x + 2)(sec x + 2) = 0

This means that;

(sec x + 2) = 0

From trigonometry, we know that sec x = 1/cos x

Thus;

(1/cos x) + 2 = 0

1/cos x = -2

cos x = -1/2

cos x = -0.5

x = cos^(-1) -0.5

x = 120°

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4.2

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Write three multiplication equations in which the product will have two zeroes.Use 50 as one of the factors
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The consumer expenditure, in dollars, for a commodity is the product of its market price, p, and the number of units demanded, x
kvasek [131]

Answer:

  (a)  x = 13000 -135p

  (b)  x = 8140

Step-by-step explanation:

(a) consumer expenditure = 13000p -135p^2 = p(13000 -135p)

    = px

so, x = 13000 -135p

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4 0
3 years ago
Find the area of an isosceles trapezoid, if the lengths of its bases are 16 cm, and 30 cm, and the diagonals are perpendicular t
Klio2033 [76]
For this case we have:
 a = 30 cm
 c = 16 cm
 We look for the length of the diagonal:
 d = x + y
 Where,
 For x:
 a ^ 2 = x ^ 2 + x ^ 2
 x = a / root (2) = 30 / root (2) = 21.2132 cm
 For y:
 c ^ 2 = y ^ 2 + y ^ 2
 y = c / root (2) = 16 / root (2) = 11.3137 cm
 The diagonal is:
 d = x + y
 d = 21.2132 + 11.3137
 d = 32.5269 cm
 Then, the height is:
 h = h1 + h2
 For h1:
 h1 = root (x ^ 2 - (a / 2) ^ 2) = root ((21.2132) ^ 2 - (30/2) ^ 2)
 h1 = 15 cm
 For h2:
 h2 = root (y ^ 2 - (c / 2) ^ 2) = root ((11.3137) ^ 2 - (16/2) ^ 2)
 h2 = 8 cm
 Finally:
 h = h1 + h2
 h = 15 + 8
 h = 23 cm
 Then, the area is:
 A = (1/2) * (a + c) * (h)
 A = (1/2) * (30 + 16) * (23)
 A = 529 cm ^ 2
 Answer:
 
the area of an isosceles trapezoid is:
 
A = 529 cm ^ 2
4 0
3 years ago
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