If (6^2)^x equals 1, what is the value of x
1 answer:
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Answer:
B
Step-by-step explanation:
let f(x) = y and rearrange making x the subject
y = ( multiply both sides by 7 to clear the fraction )
7y = x + 2 ( subtract 2 from both sides )
7y - 2 = x
Change y back into terms of x with x the inverse function, that is
p(x) = 7x - 2
