What is the answer to 846 x 21

Mathematics

2 answers:

svlad2 [7]3 years ago

5 0

Your Answer 17766

Easy

guapka [62]3 years ago

5 0

The answer is 17,766

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Type the correct answer for each.

xxTIMURxx [149]

If point $\left(x,\ \frac{\sqrt{7}}{3}\right)$ is on the unit ircle, then:

$x^2+\left( \frac{ \sqrt{7} }{3} \right)^2=1 \\ \\ \Rightarrow x^2+ \frac{7}{9} =1 \\ \\ \Rightarrow x^2=1- \frac{7}{9} = \frac{2}{9} \\ \\ \Rightarrow x= \sqrt{ \frac{2}{9} } = \frac{ \sqrt{2} }{3}$

Since, the point is in the second quadrant, x is negative.

Thus, $(x,\ y)=\left(x,\ \frac{\sqrt{7}}{3}\right)=\left(-\frac{ \sqrt{2} }{3},\ \frac{\sqrt{7}}{3}\right)$

Part A:

$3 \sqrt{7} =6\left( \frac{ \sqrt{7} }{2} \right) \\ \\ =6\left( \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \right) \\ \\ =6\left( \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } \right)=-6\left( \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } \right) \\ \\ =-6\left( \frac{y}{x} \right)=-6\tan\theta$

Therefore, $-6\tan\theta=3\sqrt{7}$ .

Part B:

$- \frac{ \sqrt{7} }{2} =- \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \\ \\ =- \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } = \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } = \frac{y}{x} \\ \\ =\tan\theta$

Therefore, $\tan\theta=- \frac{ \sqrt{7} }{2}$

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3 years ago

The graph below is the graph of which inequality?

Misha Larkins [42]

Answer:

Step-by-step explanation:

$\sqrt{x } \geqslant 1$

on your graph x is not equal to 0 starting from one and going to Infinity.

4 0

3 years ago

4 (3) + 5(6+1) please help me

Oksi-84 [34.3K]

4(3) + 5(6+1>
12 + 35
47

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

Given that (-6,2) is on the graph of f(x) find the corresponding point for the function f(1/4x).

Dafna1 [17]

Answer: (-24,2)

=======================================

Work Shown:

The y coordinate stays the same. Only the x coordinate will change.

(1/4)*x = -6
x = -6*4
x = -24 is the new x coordinate
Plugging x = -24 into f((1/4)x) leads to f(-6) = 2

7 0

4 years ago