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3 years ago

What is the answer to 846 x 21

Mathematics

2 answers:

svlad2 [7]3 years ago

5 0

Your Answer 17766

Easy

guapka [62]3 years ago

5 0

The answer is 17,766

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There are 4 lunch choices in a school cafeteria: Salad, Pizza, Spaghetti, and Sub Sandwiches. The percentage of students that ch

andrew-mc [135]

Answer:

The total number of students that ate lunch are 300 .

Step-by-step explanation:

Formula

$Percentage = \frac{Part\ value\times 100}{Total\ value}$

As given

There are 4 lunch choices in a school cafeteria: Salad, Pizza, Spaghetti, and Sub Sandwiches.

The percentage of students that chose salad is 15%.

If 45 students chose salad.

Here

Percentage = 15%

Part value = 45

Put in the formula

$15 = \frac{45\times 100}{Total\ value}$

$Total\ value= \frac{4500}{15}$

$Total\ value= 300$

Therefore the total number of students that ate lunch are 300 .

5 0

3 years ago

Read 2 more answers

|x|+5=18 <br> 5 or - 5 <br> 13 or - 13 <br> 18 or - 18 <br> 23 or - 23

slava [35]

Just transpose the 5 to the right side of 18 so it will look like this, /x/ = 18 - 5
Then get the difference and it would be 13. So to check this out if it is correct, substitute x for the value of 13 and it will look like this.
13 + 5 = 18
I hope my answer helped you.

6 0

3 years ago

Porfabor necesito ayuda en la esta pregunta. ¿Encuentra cuatro pares ordenados de la siguiente función? f(x) = X3 – 2X2 – 2

zlopas [31]

Answer:

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de $f(x) = x^{3}-2\cdot x^{2}-2$ .

Step-by-step explanation:

Un par ordenado es un elemento de la forma $(x,f(x))$ , donde $x$ es un elemento del dominio de la función, mientras $f(x)$ es la imagen de la función evaluada en $x$ . Entonces, un par ordenado que está contenido en la citada función debe satisfacer la siguiente condición:

La imagen de la función existe para un elemento dado del dominio. Esto es:

$x \rightarrow f(x)$

Dado que $f(x)$ es una función polinómica, existe una imagen para todo elemento $x$ . Ahora, se eligen elementos arbitrarios del dominio para determinar sus imágenes respectivas:

x = 0

$f(0) = 0^{3}-2\cdot (0)^{2}-2$

$f(0) = -2$

(0, -2) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 1

$f(1) = 1^{3}-2\cdot (1)^{2}-2$

$f(1) = -3$

(1, -3) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 2

$f(2) = 2^{3}-2\cdot (2)^{2}-2$

$f(2) = -2$

(2, -2) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 3

$f(3) = 3^{3}-2\cdot (3)^{2}-2$

$f(3) = 7$

(3, 7) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de $f(x) = x^{3}-2\cdot x^{2}-2$ .

6 0

2 years ago

At one time during 2001 for every 20 copies of Harry Potter and the Sorcerer's Stone that were sold 13.2 copies of Harry Potter

Airida [17]

In order to solve this, you have to take the number of copies of the Prisoner of Azkaban and divide it by the number of copies of the Sorcerer's Stone:
13.2÷20=0.66
To get this into a percentage, multiply the 0.66 by 100, and get 66%, meaning that The Prisoner of Azkaban was sold only 66% as much as The Sorcerer's Stone.

5 0

3 years ago

What is the value of this expression if h = 8,3 = -1, and k = –12?

snow_tiger [21]

Answer: C.36

Step-by-step explanation:

3 0

3 years ago