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TiliK225 [7]
3 years ago
13

This is not a multiple choice question. Please help!

Mathematics
1 answer:
Shkiper50 [21]3 years ago
5 0
Complentary angle = 90 degrees
 
90 - 16 = your answer
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Wat is the value of x in the equation<br>5x + 2(x + 1) = 4​
PIT_PIT [208]

Answer:

x = \bf~\frac{2}{7}~or~0,285

Step-by-step explanation:

5x + 2(x + 1) = 4

5x + 2x + 2 = 4 (here we got rid of the parenthesis)

7x + 2 = 4 (here we summed both of our x values)

7x = 4 - 2 (here we took #2 to the other side of the equation)

7x = 2 (we subtracted 4 - 2)

x = 2 / 7

x = \bf~\frac{2}{7}~or~0,285

Hope it helped,

BiologiaMagister

5 0
4 years ago
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A sample of a radioactive isotope had an initial mass of 360 mg in the year 1998 and
RUDIKE [14]

Answer:

193 mg

Step-by-step explanation:

Exponential decay formula:

  • A_t = A_0e^r^t
  • where Aₜ = mass at time t, A₀ = mass at time 0,  r = decay constant (rate), t = time  

Our known variables are:

  • 1998 to the year 2004 is a total of t = 6 years.
  • The sample of radioactive isotope has an initial mass of A₀ = 360 mg at time 0 and a mass of Aₜ = 270 mg at time t.

Let's solve for the decay constant of this sample.

  • 270=360e^-^r^(^6^)
  • 270=360e^-^6^r
  • \frac{3}{4} =e^-^6^r
  • \text{ln} (\frac{3}{4} )= \text{ln}(e^-^6^r)
  • \text{ln} (\frac{3}{4} )=-6r
  • r=-\frac{\text{ln}\frac{3}{4} }{6}
  • r=0.04794701

Using our new variables, we can now solve for Aₜ at t = 7 years, since we go from 2004 to 2011.

Our new initial mass is A₀ = 270 mg. We solved for the decay constant, r = 0.04794701.

  • A_t=270e^-^(^0^.^0^4^7^9^4^8^0^1^)^(^7^)
  • A_t=270e^-^0^.^3^3^5^6^2^9^0^7
  • A_t=193.01982213

The expected mass of the sample in the year 2011 would be 193 mg.

3 0
3 years ago
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The polygon is regular
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Look it up lol thats what i di
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