Answer:

Step-by-step explanation:


Answer:
We have to prove
sin(α+β)-sin(α-β)=2 cos α sin β
We will take the left hand side to prove it equal to right hand side
So,
=sin(α+β)-sin(α-β) Eqn 1
We will use the following identities:
sin(α+β)=sin α cos β+cos α sin β
and
sin(α-β)=sin α cos β-cos α sin β
Putting the identities in eqn 1
=sin(α+β)-sin(α-β)
=[ sin α cos β+cos α sin β ]-[sin α cos β-cos α sin β ]
=sin α cos β+cos α sin β- sinα cos β+cos α sin β
sinα cosβ will be cancelled.
=cos α sin β+ cos α sin β
=2 cos α sin β
Hence,
sin(α+β)-sin(α-β)=2 cos α sin β
Answer:
t = 21d
Step-by-step explanation:
Here tension and distance are denoted t by d and respectively. Since t varies directly with d , then the relation between t and d is k=td Given that, for the tension 42 pounds, the spring is stretched 2 inches. Substituting t = 42 and d= 2 into t = kd find the value of k . Therefore,
42= K (2)

K= 21
Thus the relationship is t = 21d
(Hope this helps can I pls have brainlist (crown)☺️)
86+08p because both have the answer