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2 years ago

After a reflection of the figure, the image vertices are A'(5, 1), B'(3, –1), and C'(7, –1). What is the line of reflection?

Mathematics

1 answer:

spin [16.1K]2 years ago

4 0

Answer:

A. y=2

Step-by-step explanation:

If you draw a line on y=2 and reflect it, A will be on (5,1), B will be on (3,-1), and C will be at (7,-1) Let me know if you need any more help. Have a nice day. :)

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12-0=12 that is the answer

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2 years ago

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il63 [147K]

Answer:

$x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

Step-by-step explanation:

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$\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

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2 years ago

Verify the identity

Igoryamba

Answer:

We have to prove

sin⁡(α+β)-sin⁡(α-β)=2 cos⁡ α sin ⁡β

We will take the left hand side to prove it equal to right hand side

So,

=sin⁡(α+β)-sin⁡(α-β) Eqn 1

We will use the following identities:

sin⁡(α+β)=sin⁡ α cos⁡ β+cos⁡ α sin⁡ β

and

sin⁡(α-β)=sin⁡ α cos ⁡β-cos ⁡α sin ⁡β

Putting the identities in eqn 1

=sin⁡(α+β)-sin⁡(α-β)

=[ sin⁡ α cos ⁡β+cos⁡ α sin⁡ β ]-[sin⁡ α cos ⁡β-cos ⁡α sin ⁡β ]

=sin⁡ α cos⁡ β+cos⁡ α sin ⁡β- sin⁡α cos⁡ β+cos ⁡α sin ⁡β

sin⁡α cos⁡β will be cancelled.

=cos⁡ α sin ⁡β+ cos ⁡α sin ⁡β

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Hence,

sin⁡(α+β)-sin⁡(α-β)=2 cos ⁡α sin ⁡β

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3 years ago

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Answer:

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Step-by-step explanation:

Here tension and distance are denoted t by d and respectively. Since t varies directly with d , then the relation between t and d is k=td Given that, for the tension 42 pounds, the spring is stretched 2 inches. Substituting t = 42 and d= 2 into t = kd find the value of k . Therefore,

42= K (2)

$K=\frac{42}{2}$

K= 21

Thus the relationship is t = 21d

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