Let denote the value on the
-th drawn ball. We want to find the expectation of
, which by linearity of expectation is
(which is true regardless of whether the are independent!)
At any point, the value on any drawn ball is uniformly distributed between the integers from 1 to 10, so that each value has a 1/10 probability of getting drawn, i.e.
and so
Then the expected value of the total is
Therefore the point P is at 3.46 cm from O and it lies on the angle bisector of ∠XOY
<h3>What is an Angle Bisector ?</h3>The ray that bisects the angle into half is called Angle Bisector.
It is given that ∠XOY = 60 degree
the length of OX = 4.5 cm
OY =5 cm
The point M is on OX such that
OM = 2 MX
so The M is at 3 cm from O
The point P lies in the acute angle such that the distance between point P and OX and OY is always same and at 3 cm from M
According to the angle bisector theorem converse states that if a point is in the interior of an angle and is at equal distance from the sides then it lies on the bisector of that angle.
As it can be seen from the image that a point equidistant from the rays , at 3 cm from M will be at
By Pythagoras Theorem
3² +3² = OP²
OP = 2 = 3.46 cm from O
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