Answer:
The answer would be HFG = KIJ (A)
If we know that the opposite and the adjacent side of the triangle are congruent, then the hypotenuse is congruent too. Therefor, A is correct as we know the opposite side and the adjacent side are congruent.
Answer:
Is an equivalent part of a proper fraction, expressed in split parts with denominators whose LCM is the denominator of the fraction.
Whenever a problem says "one number" and "another number" we can substitute x and y. for this we have x=2y+1 and xy=1. since we know the value of x (2y+1) we can substitute it for the other equation to get (2y+1)y=10. simplify to get 2y^2+y=10. from here you can do a few methods to solve this, but the simplest in my opinion is by factoring.
In order to factor it must be equal to 0, so we have 2y^2+y-10=0. We factor this and get y=5 (we also get y=-4 but it is an extraneous root). now we can plug that into either equation and find that x=2.
this means our two numbers are 5 and 2
Answer:
2b+9
Step-by-step explanation:
Answer: It would be 5
Step-by-step explanation:
take one of each coin 1+5+10+25 which = 41
how many times does 41 go into 205
41x5=205
Hope this helps
