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ludmilkaskok [199]
3 years ago
6

Point R(5,-3) and point N(9,-4) are on line k. What is the slope of the line passing through these points?

Mathematics
1 answer:
Aleks04 [339]3 years ago
8 0
The slope of a line, denoted "m" is:

m=(y2-y1)/(x2-x1), where (x1,y1) and (x2,y2) are any two points on the line.

m=(-4--3)/(9-5)

m=-1/4

So the slope is negative one quarter.
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Irina18 [472]

Answer:

Step-by-step explanation:

Let the ends of the given segment are A and B.

Coordinates of A → (8, 6)

Coordinates of B → (12, 12)

If a point (x, y) is dilated by a scale factor 'k' about the origin, rule to be followed,

(x, y) → (kx, ky)

If k = \frac{2}{3}

(x, y) → (\frac{2}{3}x, \frac{2}{3}y)

By this rule coordinates of the image points of A and B will be,

A(8, 6) → A'(\frac{2\times 8}{3},\frac{2\times 6}{3})

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B(12, 12) → B'(\frac{12\times 2}{3}, \frac{12\times 2}{3})

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Now we can get the image of segment AB after dilation by a scale factor of \frac{2}{3}.

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3 years ago
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Nezavi [6.7K]

Answer:

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Step-by-step explanation:

Two vectors (x_1,\, y_1) and (x_2,\, y_2) are parallel to one another if and only if the ratio between their corresponding components are equal:

\displaystyle \frac{x_1}{x_2} = \frac{y_1}{y_2}.

Equivalently:

\displaystyle \frac{x_1}{y_1} = \frac{x_2}{y_2}.

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\displaystyle \frac{a}{4} = \frac{2}{5}.

Solve for a:

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3 years ago
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Sedaia [141]

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b

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because thats the answer

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