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3 years ago

Songs To Make You Feel Happy

Mathematics

2 answers:

DanielleElmas [232]3 years ago

8 0

Awe thanks.
I like....

3 birds (bob Marley)
Lucy (skillet)
Step into my life (powfu)

Neko [114]3 years ago

5 0

Answer:

I liked most of hem you have agood taste in music

Step-by-step explanation:

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2 A cafe sells cakes and scones.

Alecsey [184]

30 cakes on tuesday

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3 years ago

At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel

Alexeev081 [22]

Use Law of Cooling:
$T(t) = (T_0 - T_A)e^{-kt} +T_A$
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
$42 = (80-20)e^{-3k} +20 \\ \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\ \\ k = -\frac{1}{3} ln (\frac{11}{30})$

Substituting k back into cooling equation gives:
$T(t) = 60(\frac{11}{30})^{t/3} + 20$

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
$T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\ \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80$
Solve for x:
$x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80$
Sub back into original cooling equation, x = T(t)
$-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20$
Solve for t:
$60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3} = 60 \\ \\ (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\ \\ \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\ \\ \\ t = 4.959$

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM

8 0

4 years ago

Cynthia completed 2/3 of the items on her to - do listin the morning and finished 1/6 of the items during her lunch break. Wht f

adell [148]

She finished 5/6 of her work and still has 1/6 do to.

4 0

3 years ago

Read 2 more answers

Find the least common multiple of 18 ,12 , and .14

sladkih [1.3K]

Hello!
I'm assuming that the values you gave are 18, 12 and 14, but there's a period before the 14, I think that's a mistake but if it's not please let me know, anyhow, the least common multiple of 12, 14 and 18 is 252.

Good luck!

6 0

3 years ago

Read 2 more answers

Let f(x) = 2x - 1 and g(x) = x2 + 5.<br> Find (fog)0).

Andru [333]

Answer:

3x^2 - x^2 - 5

Step-by-step explanation:

since f(x) = 2x - 1 and g(x) = x^2 + 5

((2x - 1)(x^2+5)) multiply

3x^2 - x^2 - 5

3 0

3 years ago