Let’s call the speed of the slower car S, then the speed of the other is S+10mph.
At 5pm they have been travelling for 3 hours. The slower car travels a distance 3S and the faster one 3(S+10).
But the two distances must add up to 240 miles so 3S+3(S+10)=240, 3S+3S+30=240, 6S=210, S=35 mph. The faster car’s speed is 45mph. We can see that 3S is the same distance as 3x, so x=S=35 mph, and the distance the faster car travels is 3×45=135 miles.
-30 i believe. If it’s wrong sorry
Answer:
a d and e
Step-by-step explanation:
none
Answer:
m<BGC = 145°
Step-by-step explanation:
<AGC and <DGB are vertical angles. Vertical angles are congruent. Therefore:
m<AGC = m<DGB
(substitution)
Collect like terms
Divide both sides by -5
x = 5
m<BGC = 180 - (m<AGC) (linear pair)
m<BGC = 180 - (3x + 20)
Plug in the value of x
m<BGC = 180 - (3(5) + 20) = 180 - 35
m<BGC = 145°
1) 96 * 6 2/3%= 6.4
2) 750 * 33 1/3%= 250
3) 240 * 66 1/2%= 159.6
Hope this helps! :)