Compare 1/7 to consecutive multiples of 1/9. This is easily done by converting the fractions to a common denominator of LCM(7, 9) = 63:
1/9 = 7/63
2/9 = 14/63
while
1/7 = 9/63
Then 1/7 falls between 1/9 and 2/9, so 1/7 = 1/9 plus some remainder. In particular,
1/7 = 1/9¹ + 2/63.
We do the same sort of comparison with the remainder 2/63 and multiples of 1/9² = 1/81. We have LCM(63, 9²) = 567, and
1/9² = 7/567
2/9² = 14/567
3/9² = 21/567
while
2/63 = 18/567
Then
2/63 = 2/9² + 4/567
so
1/7 = 1/9¹ + 2/9² + 4/567
Compare 4/567 with multiples of 1/9³ = 1/729. LCM(567, 9³) = 5103, and
1/9³ = 7/5103
2/9³ = 14/5103
3/9³ = 21/5103
4/9³ = 28/5103
5/9³ = 35/5103
6/9³ = 42/5103
while
4/567 = 36/5103
so that
4/567 = 5/9³ + 1/5103
and so
1/7 = 1/9¹ + 2/9² + 5/9³ + 1/5103
Next, LCM(5103, 9⁴) = 45927, and
1/9⁴ = 7/45927
2/9⁴ = 14/45927
while
1/5103 = 9/45927
Then
1/5103 = 1/9⁴ + 2/45927
so
1/7 = 1/9¹ + 2/9² + 5/9³ + 1/9⁴ + 2/45927
One last time: LCM(45927, 9⁵) = 413343, and
1/9⁵ = 7/413343
2/9⁵ = 14/413343
3/9⁵ = 21/413343
while
2/45927 = 18/413343
Then
2/45927 = 2/9⁵ + remainder
so
1/7 = 1/9¹ + 2/9² + 5/9³ + 1/9⁴ + 2/9⁵ + remainder
Then the base 9 expansion of 1/7 is
0.12512..._9
We know there are 60 minutes in an hour. To find 2/3 of an hour we divide 60/3 to find 1/3 and multiply by 2 so:
60/3 = 20
20*2 = 40 minutes (which is 2/3 of an hour) to do science
We do the same thing with the 40 minutes. To find 1/4 of 40 minutes we divide 40 by 4 and then multiply it by 3 to get 3/4 so:
40/4 = 10
10*3 = 30 minutes
Then subtract the times 40-30 = 10 minutes
It took her 10 more minutes to complete her science homework.
Hope that helps
Answer:
C
Step-by-step explanation:
A: Perpendicular lines have 1 solution. A is not the answer.
B: If the lines intersect, there is one solution, not many.
C: The lines are the same or can be reduced to being the same. C is the answer.
D: The lines don't intersect means that the lines are parallel. There isn't a solution.
When her lung had been reduced below $5000 she could pay the rest and must know how many payments were left because there's a grand total of 10 payments. So let's, uh let's plot these out. Um, so I'm gonna plot a line of why equals 5000 and I'm gonna plant a line, someone have a Y equals 5000. And then there's a formula for that was found in the text to find the amount left over as our times one minus one plus I to the negative in minus X. However, I will tell us how much is left to be paid. So what I'm gonna put into my why equals as I'm gonna put 24 65 82 times one minus 1.0 for to the negative 10 minus sex all over 0.4 Okay, so let's go put that in into our computations. Just clearing my wine menus. 5000 and I'm going to have our values. 24 65.82 times one minus 1.0 for to the negative parentheses. 10 minus acts and divided by zero You hear before. And so that happens at 7.816 payments. So somewhere after her seventh payment on before her eighth payment eso when she goes under, that will be for her eighth payment. Um, so eighth payment puts her under 5000 on, then. Now the eight payments air done. That means, uh that she will have to payments left over. And I think that's what the question was asking. So there were two payments left.
Answer:5326
Step-by-step explanation:
A=Pe^rt
