Your equation is not dimensionally consistent.
Let L = length and T = time. Without taking into account precise units, you can write velocity as the ratio between some distance L and some time T.
So in terms of these fundamental quantities, your equation can be written as
L = (L/T + L/T)T^2
L = (L + L)T
L = LT
Answer:
90% of people marry their 7th-grade love. since u have read this, u will be told good news tonight. if u don't pass this on nine comments your worst week starts now this isn't fake. apparently, if u copy and paste this on ten comments in the next ten minutes you will have the best day of your life tomorrow. you will either get kissed or asked out in the next 53 minutes someone will say I love you
Step-by-step explanation:
Answer:
2,8,32,128,512
Step-by-step explanation:
f(x)=f(x-1)*4
f(1)=2
f(2)=f(2-1)*4=f(1)*4=2*4=8
f(3)=f(3-1)*4=f(2)*4=8*4=32
f(4)=f(4-1)*4=f(3)*4=32*4=128
f(5)=f(5-1)*4=f(4)*4=128*4=512
Answer:
-4
Step-by-step explanation:
i just took this
Answer:
x = 6.00 $/kg ----> almond
y = 3.5 $/kg ------> nut
Step-by-step explanation:
To find the price per kg of each product you first write the algebraic equations for the given relations:
x : price per kg of almond
y: price per kg of nut
Then, you have:
5x + 4y = 44.00 (1)
8x + 6y = 69.00 (2)
By using substitution you have from (1):
y = (44.00-5x)/(4) = 11.00 - (5/4)x
you replace this expression for y into (2):
8x+6[11.00-(5/4)x] = 69.00
8x+66.00-(15/2)x = 69.00
8x-(15/2)x = 69.00 - 66.00
(1/2)x = 3.00
x = 6.00 $/kg ----> almond
And for nut:
y = 11.00 - (5/4)x = 11.00 - (5/4)(6.00) = 3.5$/kg
y = 3.5 $/kg ------> nut
