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Anestetic [448]
3 years ago
6

What is the surface area of the right prism given below?

Mathematics
1 answer:
Anna [14]3 years ago
7 0

Answer:

D. 504\text{ units}^2

Step-by-step explanation:  

We have been an image of a right prism. We are asked to find the surface area of our given prism.

We will use surface area of prism formula to solve our given problem.

\text{Surface area of right prism}=p\cdot h+2B, where,

p = Perimeter of base of prism,

h = Height of prism,

B = Area of base of prism.  

Now, we need to find the third side of triangular base of prism using Pythagoras theorem.

x^2=8^2+6^2

x^2=64+36

x^2=100

x=\sqrt{100}

x=10

Upon substituting our given values in above formula we will get,

\text{Surface area of right prism}=(10+8+6)\cdot 19+2(\frac{1}{2}\times 6\times 8)

\text{Surface area of right prism}=(24)\cdot 19+(48)

\text{Surface area of right prism}=456+(48)

\text{Surface area of right prism}=504

Therefore, the surface area of our given prism is 504 square units and option D is the correct choice.

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</span>x^2+(x+2)^2=130 \ \ \  \ \ \ [x\ \textgreater \ 0] \\ x^2+x^2+4x+4-130=0 \\ 2x^2+4x-126=0 \\ x^2+2x-63=0 \\ D=b^2-4ac=2^2-4*1*(-63)=4+252=256 \\ x_{1,2}= \frac{-bб \sqrt{D} }{2a}= \frac{-2б  \sqrt{256}  }{2*1}=  \frac{-2б16 }{2}\\x_1=-9 \ \ \ \ \O\\x_2=7
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