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3 years ago

What is x if 4x-79=3x-29

2 answers:

6 0

4x-79=3x-29

Move the terms with "x" on the left, and the numbers on the right.

4x-3x=79-29
x=50

Tom [10]3 years ago

5 0

4x-79=3x-29 <=> 4x-3x=-29-(-79) <=> x=50

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A (non-zero) number multiplied by zero equals zero, whereas a non-zero number divided by zero is undefined.

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2 years ago

The ratio of Mary’s downloaded iPad apps to Katie’s is 12 to 8. If Katie has 96 apps how many does Mary have?

sladkih [1.3K]

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2 years ago

What are fractions that are greater than 4 1/3 but less than 5 2/3

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3 years ago

A(c−b)=d solve for c

Rainbow [258]

Answer:

The solution to this equation could not be determined.

Step-by-step explanation:

Simplifying

a(c + -1b) = d

Reorder the terms:

a(-1b + c) = d

(-1b * a + c * a) = d

(-1ab + ac) = d

Solving

-1ab + ac = d

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Combine like terms: d + -1d = 0

-1ab + ac + -1d = 0

The solution to this equation could not be determined.

4 0

2 years ago

A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data

Rasek [7]

Answer: a. 1.981 < μ < 2.18

b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

$\overline{x}=\frac{\Sigma x}{n}$

$\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}$

$\overline{x}=$ 2.08

Now, we estimate standard deviation:

$s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }$

$s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }$

s = 0.1564

For t-score, we need to determine degree of freedom and $\frac{\alpha}{2}$ :

df = 12 - 1

df = 11

$\alpha$ = 1 - 0.95

α = 0.05

$\frac{\alpha}{2}=$ 0.025

Then, t-score is

$t_{11,0.025}$ = 2.201

The interval will be

$\overline{x}$ ± $t.\frac{s}{\sqrt{n} }$

2.08 ± $2.201\frac{0.1564}{\sqrt{12} }$

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

8 0

3 years ago