The diagram shows that FG = IJ are congruent segments due to the double tickmarks. These are the hypotenuses of the right triangles.
So that takes care of the "H" in "HL".
The L stands for "leg", so we need to have a congruent pair of corresponding legs.
Due to the orientation of the triangles, it's not clear how the corresponding legs match up, but if any of the following is true
- EF = IK
- EF = JK
- EG = IK
- EG = JK
then we'd have enough to use HL.
Answer:
Step-by-step explanation:
Essentially, begin by flipping the x and y terms:
x = (1 - 2y)^2 + 5
Then, solve for y:
Because we know there is only 1 y-value for any given x-value, the inverse of the given function is also a function.
Answer:
Step-by-step explanation:
Let the horizontal distance is x
<u>Use tangent to solve this:</u>
- tan 30° = 6/x
- x = 6 / tan 30°
- x = 10.4 mi (rounded)
Answer:
y = 2/3x
Step-by-step explanation:
So we know, when lines are perpendicular that they share the same slope. The slope in the equation of y = 2/3x + 7 is 2/3x. So, we have our slope. Now, we just need to find our b. We plug in the point that you gave us into the equation y = mx + b.
3 = 2/3(2) + b
we multiply the denominator 3 by 2, then divide that by the numerator 2.
3 = 3 + b
subtract 3 from itself and from the opposite side of the equal side 3.
0 = b
in the end, there is no b for this equation. Our answer is
y = 2/3x
4 is the constant varriation
