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Rasek [7]
3 years ago
6

Show work pls What is the equation in slope-intercept form of the line that passes through the point (2, -2) and is perpendicula

r to the line represented by
y=2/5x +2 ?

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
6 0

Answer:

Step-by-step explanation:

the slope-International cept frome y= mx + b was where m is the slope and b y-intercept

y=mx +b

m= -2/5

b=2

slope is :2/5

y-intercept is :2

x.   y  

0.  2

1    8/5

Alekssandra [29.7K]3 years ago
4 0

Answer:

Step-by-step explanation:

perp. -5/2

y + 2 = -5/2(x - 2)

y + 2 = -5/2x + 5

y = -5/2x + 3

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Answer:

<u />\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \boxed{ \frac{1}{4} }

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<em>Identify given limit</em>.

\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3}

<u>Step 2: Find Limit</u>

Let's start out by <em>directly</em> evaluating the limit:

  1. [Limit] Apply Limit Rule [Variable Direct Substitution]:
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  2. Evaluate:
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When we do evaluate the limit directly, we end up with an indeterminant form. We can now use L' Hopital's Rule to simply the limit:

  1. [Limit] Apply Limit Rule [L' Hopital's Rule]:
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  2. [Limit] Differentiate [Derivative Rules and Properties]:
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  3. [Limit] Apply Limit Rule [Variable Direct Substitution]:
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  4. Evaluate:
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∴ we have <em>evaluated</em> the given limit.

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Learn more about limits: brainly.com/question/27807253

Learn more about Calculus: brainly.com/question/27805589

___

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

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