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Rasek [7]
3 years ago
6

Show work pls What is the equation in slope-intercept form of the line that passes through the point (2, -2) and is perpendicula

r to the line represented by
y=2/5x +2 ?

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
6 0

Answer:

Step-by-step explanation:

the slope-International cept frome y= mx + b was where m is the slope and b y-intercept

y=mx +b

m= -2/5

b=2

slope is :2/5

y-intercept is :2

x.   y  

0.  2

1    8/5

Alekssandra [29.7K]3 years ago
4 0

Answer:

Step-by-step explanation:

perp. -5/2

y + 2 = -5/2(x - 2)

y + 2 = -5/2x + 5

y = -5/2x + 3

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Hope I helped

Best of luck (:



4 0
3 years ago
I need help dont know how to do this.
UkoKoshka [18]
To solve the question we need to calculate the equation of the straight line;
the equation is given by:
m=(y1-y)/(x2-x)
where;
m is the slope;
selecting 2 points from the graph say (0,2) and (2,0), the slope of the graoh will be:
m=(0-2)/(2-0)=-1
thus using point (-2,4) the equation will be given by:
-1=(y-4)/(x+2)
-1(x+2)=(y-4)
this can be written as:
-x-2=y-4
this can be written as:
y+2=-x+4
this can be written as:
y+2=-(x-2)
The answer is A.y+2=-(x-2)
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