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lana66690 [7]
3 years ago
5

Verify the identity by transforming the left-hand side into the right-hand side.

Mathematics
1 answer:
qaws [65]3 years ago
8 0
<span>(1 + cos² 3θ) / (sin² 3θ) = 2 csc² 3θ - 1

Starting with the left:  Note that  cos²θ + </span><span>sin²θ = 1.
In the same way:    </span><span>cos²3θ + <span>sin²3θ = 1
</span></span>Therefore                cos²3θ  = 1 - <span>sin²3θ
</span> From the top:  (1 + cos² 3θ) = 1 + 1 - sin²3θ = 2 - <span>sin²3θ
</span>
(1 + cos² 3θ) / (sin² 3θ) = (<span>2 - sin²3θ) / (sin² 3θ) = 2/</span><span>sin² 3θ - </span><span>sin²3θ/</span>sin²3θ

=  2/<span>sin² 3θ - 1;        But 1/</span><span>sinθ = csc</span><span>θ,  Similarly  </span>1/sin3θ = csc3θ

= 2 *(1/sin<span>3θ)²  - 1</span>
= 2csc²3θ  - 1.        Therefore  LHS = RHS.  QED.

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We have the following given
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p2 - probability for outcome 2
p3 - probability for outcome 3
v1 - amount of money that you will win or lose for outcome 1
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4 years ago
Suppose that the store manager of a small rural pharmacy is doing a linear regression of daily sales of over-the-counter (OTC) d
Doss [256]

Answer:

3.83

Step-by-step explanation:

Mean of x = Σx / n

Mean of x = (14 + 19 + 13 + 6 + 9) / 5 = 12.2

Sum of square (SS) :

(14-12.2)^2 + (19-12.2)^2 + (13-12.2)^2 + (6-12.2)^2 + (9-12.2)^2 = 98.8

Mean of y = Σy / n

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Σ(y - ybar)² = (101-61.2)^2 + (89-61.2)^2 + (48-61.2)^2 + (21-61.2)^2 + (47-61.2)^2 = 4348.8

df = n - 2 = 5 - 2 = 3

Σ(y - ybar)² / df = 4348.8 / 3 = 1449.6

√(Σ(y - ybar)² / df) = √1449.6 = 38.074

Standard Error = √(Σ(y - ybar)² / df) / √SS

Standard Error = 38.074 / √98.8

Standard Error = 3.83

4 0
3 years ago
What is the distance between point A(2,9) and B(-2,6)
Katyanochek1 [597]

Answer:

The distance among those points is 5 units

Step-by-step explanation:

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3 years ago
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the other point could be 2.8

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in circle values of both x and are almost equal in magnitude

since 2.8 is closest to 3 i magnitude

hence 2.8 will  be correct option

this point will lie in third coordinate

as  third coordinate has points

(-x,y)

and coordinates of points lie on the circle are

(-3,2.8)

8 0
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