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3 years ago

(-5,-3), parallel to y=6/5x+4

1 answer:

8 0

<span>(-5,-3), parallel to y=6/5x+4

</span><span>parallel lines have same slope so slope = 6/5

y + 3 = 6/5(x + 5)
y + 3 = 6/5 x + 6
y = 6/5 x + 3

answer
equation
</span>y = 6/5 x + 3

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Sara has lived 18.0 years. How many seconds has she lived? Express the answer in scientific notation. Use 365.24 days per year f

Contact [7]

Answer:

She has lived $5.68021248\times 10^8\ \text{seconds}$ .

Step-by-step explanation:

Given : Sara has lived 18.0 years.

To find : How many seconds has she lived?

Solution :

Using conversions,

1 year = 365.24 days

1 day = 24 hours

1 hour = 60 minutes

1 minute = 60 seconds

Converting 18 years into seconds,

$18 \text{years} = 18\times 365.24\times 24\times 60\times 60\ \text{seconds}$

$18 \text{years} =568021248\ \text{seconds}$

In scientific notation,

$18 \text{years} =5.68021248\times 10^8\ \text{seconds}$

Therefore, she has lived $5.68021248\times 10^8\ \text{seconds}$ .

4 0

3 years ago

Solve for x and y<br><br>6/x+2y + 5/x-2y = -3 ;<br>3/x+2y + 7/x-2y = -6

Radda [10]

Step-by-step explanation:

Let

{1/(x+2y)} = u -----Eqn(1)

{1/(x-2y)} = v ------Eqn(2)

So, given equation can be rewritten as

⇛6u + 5v = -3 ---Eqn(3)

⇛3u + 7v = -6 -----Eqn(4)

On multiply equation (4) by 2, we get

⇛6u + 14v = -12 -----Eqn(5)

On subtracting equation (3) from equation (5), we get

⇛9v = -9

⇛v = -9/9

⇛v = -1 ----Eqn(6)

Put value of v in equation (3), we get

6u + 5v = -3

⇛6u + 5 * (-1) = -3

⇛6u -5 = -3

⇛6u = -3 + 5

⇛6u = 2

⇛u = 2/6

⇛u = (2÷2)/(6÷2)

⇛u = 1/3 -----Eqn(7)

Now, substituting value of u and v in equation (1) and equation (2), we get

{1/(x+2y)} = 1/3 and {1/(x-2y)} = -1

⇛x + 2y = 3 -----Eqn(8)

⇛x - 2y = -1 -------Eqn(9)

Now, add equation (8) and equation (9) , we get

⇛2x = 2

⇛x = 2/2

On substituting x = 1 in equation (8), we get

x + 2y = 3

⇛ 1 + 2y = 3

⇛2y = 3 - 1

⇛2y = 2

⇛y = 2/2

Therefore, x = 1 and y = 1

<u>Answer</u><u>:</u> Hence the value of x and y is 1 and 1.

8 0

2 years ago

Determine if (-1,9) and (-2,6) are solutions to the system of equations: x + y = 8 x2 + y = 10 A) Both are solutions B) Neither

Dahasolnce [82]

Answer:

D) Only (-1,9) is a solution.

Step-by-step explanation:

x+y =8

x^2 + y = 10

Lets check the first point (-1,9)

Put in x =-1 y =9

x+y =8

-1+9 = 8

8 =8

This works

x^2 + y = 10

(-1)^2 +9 =10

1+9 = 10

10 = 10

This works

Lets check the second point (-2,6)

Put in x =-2 y =6

x+y =8

-2+6 = 8

4=8

This does not work

We can stop now. (-2,6) cannot be a solution

7 0

3 years ago

(ab^2 x -b^4a^3)^2<br><br> What is the answers

Umnica [9.8K]

Answer:

$\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8$

Step-by-step explanation:

Given the expression

$\left(ab^2\:x\:-b^4a^3\right)^2$

solving the expression

$\left(ab^2\:x\:-b^4a^3\right)^2$

$\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2$

$a=ab^2x,\:\:b=b^4a^3$

so the expression becomes

$=\left(ab^2x\right)^2-2ab^2xb^4a^3+\left(b^4a^3\right)^2$

$=a^2b^4x^2-2a^4b^6x+a^6b^8$

Thus,

$\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8$

3 0

2 years ago

46h+56h=600 please solve

valentinak56 [21]

Answer:

5.88235294118

Step-by-step explanation:

Step 1:

46h + 56h = 600 Equation

Step 2:

102h = 600

Step 3:

h = 600 ÷ 102

Answer:

h = 5.88235294118

Hope This Helps :)

3 0

3 years ago