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3 years ago

(-5,-3), parallel to y=6/5x+4

1 answer:

8 0

<span>(-5,-3), parallel to y=6/5x+4

</span><span>parallel lines have same slope so slope = 6/5

y + 3 = 6/5(x + 5)
y + 3 = 6/5 x + 6
y = 6/5 x + 3

answer
equation
</span>y = 6/5 x + 3

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Which graph is an example of a function whose parent graph is of the form y = √x?

Maksim231197 [3]

Answer:

The correct option is 1.

Step-by-step explanation:

The given parent function is

$y=\sqrt{x}$

1. Domain of the function is all positive real number including 0.

2. Range of the function is all positive real number including 0.

3. It is an increasing function. It increases at decreasing rate.

First graph increase at decreasing rate and it starts from (-4,-1), therefore the required function is

$y=\sqrt{x+4}-1$

Therefore graph 1 is an example of a function whose parent graph is of the form y = √x.

Second graph is a parabola, so it is the graph of a quadratic function.

Third graph is a rectangular hyperbola, so it is the graph of a rational functions.

Fourth graph is increasing at increasing rate, so it is the graph of an exponential function.

Therefore options 2, 3 and 4 are incorrect.

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3 years ago

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3 years ago

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A decorative window is made up of a rectangle with semicircles at either end. The ratio of AD to AB is 3:2 and AB is 30 inches.

scZoUnD [109]

Answer: The required ratio will be

$84:1034$

Step-by-step explanation:

Since we have given that

Ratio of AD to AB is 3:2

Length of AB = 30 inches

So, it becomes

$2x=30\\\\x=\frac{30}{2}=15\ inches$

So, Length of AD becomes

$3x=3\times 15=45\ inches$

Now, at either end , there is a semicircle.

Radius of semicircle along AB is given by

$\frac{30}{2}=15\ inches$

So, Area of semicircle along AB and CD is given by

$2\times \frac{\pi r^2}{2}\\\\=\frac{22}{7}\times 15\times 15\\\\=\frac{4950}{7}\ in^2$

Radius of semicircle along AD is given by

$\frac{45}{2}=22.5\ inches$

Area of semicircle along AD and BC is given by

$2\times \frac{1}{2}\pi r^2\\\\=\frac{22}{7}\times \frac{45}{2}\times \frac{45}{2}\\\\=\frac{445500}{28}\ in^2$

And the combined area of the semicircles is given by

$\frac{4950}{7}+\frac{445500}{28}\\\\=\frac{465300}{28}\ in^2$

Area of rectangle is given by

$Length\times width\\\\=AD\times AB\\\\=45\times 30\\\\=1350\ in^2$

Hence, Ratio of the area of the rectangle to the combined area of the semicircles is given by

$1350:\frac{465300}{28}\\\\=1350\times 28:465300\\\\=37800:465300\\\\=84:1034$

Hence, the required ratio will be

$84:1034$

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2 years ago

Marvin used a customary unit of measure to estimate the weight of a watermelon he grew in his backyard what could the estimated

Andrej [43]

Answer:

Usually pounds (lb) .About an an average of 20 to 25 pounds (lbs)

Step-by-step explanation:

Since Marvin uses Customary units, and considering the Watermelon.

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He could choose another customary units, but it wouldn't be practical and unusual to say a watermelon of 160 quarters, also it would leave all the listeners without parameters.

So, definitely pounds.

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3 years ago

Step by step how to solve ? 16x^2-10.3x+10=

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Answer:

it is not possible result is not given so it is not possible

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