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3 years ago

1) The measures of the angles of a triangle are in the ratio of 1:3:6. What are the measures of the angles?

Mathematics

2 answers:

stellarik [79]3 years ago

8 0

Answer:

1: 18 3: 54 6: 108

Step-by-step explanation:

A triangle has 180 degrees.

You need to add up all the ratios 1+3+6

Then divide that by 180----> 180/10=18

Then multiply all the ratios by but answer(18)

1*18=18

3*18=54

6*18=108

stira [4]3 years ago

4 0

Answer:Answered 2 years ago. The total of the sum of the measures of any triangle has been proven to be 180 degrees. If the ratio of angle measure is 1:3:6.

Step-by-step explanation:

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PLEASE HELP! I'm on a timer!

arlik [135]

The equation of a circle uses the following formula:

$(x - h)^{2} + (y - k)^{2} = r^{2}$

The center of the circle is given by (h,k). Therefore, h = -2, and k = -5. r = 1, so we can find the equation from the information given to us.

Plug in your values.

$(x + 2)^{2} + (y + 5)^{2} = 1^{2}$

$1^{2} = 1$

The equation of this circle is as follows:

$(x + 2)^{2} + (y + 5)^{2} = 1$

8 0

3 years ago

Find the limit, if it exists. (If an answer does not exist, enter DNE.) lim (x, y) → (0, 0) x4 − 34y2 x2 + 17y2

HACTEHA [7]

Answer:

Step-by-step explanation:

Given the limit of the function $\lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}$ , to find the limit, the following steps must be taken.

Step 1: Substitute the limit at x = 0 and y = 0 into the function

$= \lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}\\= \frac{0^4-34(0)^2}{0^2+17(0)^2}\\= \frac{0}{0} (indeterminate)$

Step 2: Substitute y = mx int o the function and simplify

$= \lim_{(x,mx) \to (0,0)} \frac{x^4-34(mx)^2}{x^2+17(mx)^2}\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^4-34m^2x^2}{x^2+17m^2x^2}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2(x^2-34m^2)}{x^2(1+17m^2)}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2-34m^2}{1+17m^2}\\$

$= \frac{0^2-34m^2}{1+17m^2}\\\\= \frac{34m^2}{1+17m^2}\\\\$

<em>Since there are still variable 'm' in the resulting function, this shows that the limit of the function does not exist, Hence, the function DNE</em>

4 0

3 years ago

Write the first four terms of a geometric sequence. Using the values you have written, calculate the common ratio and write the

sukhopar [10]

Answer:

FIRST FOUR (4) TERM = 6, 18, 54,162.

COMMON RATIO = 3

Step-by-step explanation:

In geometric expression.

Tn = the nth term

a = first term

r = common ratio.

Let's take the First term of the G.P as 6 and the third term as 54. Let's find the common ratio.

3rd term will be written as:

T3 = ar² = 54

Given the first term as 6.

T3 = 6r² = 54

6r² = 54

r² = 54 / 6

r² = 9

r= √9

r = 3

Therefore common ratio = 3.

Let's use this information to get the fourth term.

T4 = ar³

when a = 6

and r = 3.

T4 = 6 * 3³

T4 = 6 * 27

T4 = 162

6 0

3 years ago

Help me pls thank you

larisa [96]

Answer:

i believe it is 72 it might be incorrect though

Step-by-step explanation:

you do 44 multiplied by 36 and the divide that by 22 which gets you 72

4 0

3 years ago

Read 2 more answers

2.Assume that x is a binomial random variable with n=1000 and p=0.50. Use a normal approximation to find each of the following p

natima [27]

Answer:

a) 0.4761

b) 0.2118

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .