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jeka57 [31]
3 years ago
8

Use the diagram. AB is a diameter and AB perpendicular to CD. The figure is not drawn to scale. Which statement is NOT true?

Mathematics
2 answers:
drek231 [11]3 years ago
8 0
A. The arc length AC is not congruent to arc BD.
Sindrei [870]3 years ago
4 0

Answer:

arc AC is congruent to arc BD

Step-by-step explanation:

By drawing the perpendicular CD we get some congruent triangles, first we have ΔACP = ΔADP.

Thus, since these two triangles are congruent, we have that their sides and angles are congruent.

So, AC = AD

But we also got the congruent triangles ΔCPB and ΔDPB, where we will have congruent angles and sides:

So, ∠PBC = ∠DBP = ∠DBA

Finally, we get the congruent triangles ΔABC and ΔABD where ∠BDA = ∠ACB

Thus the statement which is not true is that arc AC is congruent to arc BD

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Out of the total respondents, the percentage of respondents from the 46–55 age group who rated the film excellent is %. write yo
Mrrafil [7]

Missing data:

Viewer's Age Group  Excellent Good Average Poor Marginal Total

16–25                          52                 42       12       7           113

26–35                          33                50         5       9          97

36–45                          58                 12       28      34         132

46–55                          25                17       22       12            76

56 +                               12                 5          3         8             28

Marginal Total             180               126      70      70           446

A rating of good or excellent indicates the audience liked the movie, while a rating of poor indicates the audience disliked the movie.

<h3>How to determine the rating of the film from the 46–55 age group?</h3>

A movie producer accomplished a survey behind a preview screening of her latest movie to estimate how the film would be accepted by viewers from various age groups. The table displays the numbers of viewers in various age groups who ranked the film excellent, good, average, and poor.

25/446 = 0.05605

0.05605 * 100% = 5.605%

Out of the entire respondents, the percentage of respondents from the 46–55 age group who ranked the film excellent exists at 5.605%.

To learn more about data refer to:

brainly.com/question/4219149

#SPJ4

3 0
1 year ago
Find the standard deviation of the data, 12, 19, 9.
jek_recluse [69]

Answer:

4.19

Step-by-step explanation:

Find the mean:

\text{Mean}=\frac{12+19+9}{3}=\frac{40}{3}

Find the standard deviation:

\text{Standard Deviation}=\sqrt{\frac{(12-\frac{40}{3})^2+(19-\frac{40}{3})^2+(9-\frac{40}{3})^2}{3}}=\sqrt{\frac{158}{9}}\approx4.19

4 0
2 years ago
Find the surface area of the composite figure.
Sloan [31]

With the help of the <em>area</em> formulae of rectangles and triangles and the concept of <em>surface</em> area, the <em>surface</em> area of the composite figure is equal to 276 square centimeters.

<h3>What is the surface area of a truncated prism?</h3>

The <em>surface</em> area of the <em>truncated</em> prism is the sum of the areas of its six faces, which are combinations of the areas of rectangles and <em>right</em> triangles. Then, we proceed to determine the <em>surface</em> area:

A = (12 cm) · (4 cm) + 2 · (3 cm) · (4 cm) + 2 · (12 cm) · (3 cm) + 2 · 0.5 · (12 cm) · (5 cm) + (5 cm) · (4 cm) + (13 cm) · (4 cm)

A = 48 cm² + 24 cm² + 72 cm² + 60 cm² + 20 cm² + 52 cm²

A = 276 cm²

With the help of the <em>area</em> formulae of rectangles and triangles and the concept of <em>surface</em> area, the <em>surface</em> area of the composite figure is equal to 276 square centimeters.

To learn more on surface areas: brainly.com/question/2835293

#SPJ1

7 0
10 months ago
Math question down below
dangina [55]

Answer:

c.

Step-by-step explanation:

10.98/2=5.49

16.19/3=5.40

21.15/4=5.29

26.85/5=5.37

4 0
3 years ago
So the equation 12 y equals 132 the equation 12 y equals 132
OlgaM077 [116]
12y = 132

Now, solve for y.

Do the inverse operation.

12y = 132
12y/12 = 132/12
y= 132/12
y= 11

Equation: 12y = 132
Y equals: 11
4 0
2 years ago
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