Answer:
JKLM is a parallelogram
Explanation:
The slope m of a line through two points (x1,y1) and (x2,y2)is given by the formula:
m=Δy/Δx=y2-y1/x2-x1
So the slopes of the sides of our quadrilateral are:
mJK=(−1)−24−(−3)=−37
mKL=(−5)−(−1)2−4=2
mLM=(−2)−(−5)−5−2=−37
mMJ=2−(−2)(−3)−(−5)=2
So JK is parallel to LM and KL is parallel to MJ
So JKLM is a parallelogram.
Answer:
the answer is c
Step-by-step explanation:
Step-by-step explanation:
I think that is the right answer I hope ut helps
Answer:
center : (0, 2.25)
radius: 14/13
Step-by-step explanation:
x^2+(y-2.25)^2=196/169
Rewrite x^2+(y-2.25)^2=196/169
(x-0)^2+(y-2.25)^2=(14/13)^2
c=(0,2.25),r= (14/13)
hope this helps<3
Yes, you can; based on the inherent assumption that the "two radicals that have negative values" are, in fact, "imaginary numbers" .
Take, for example, the commonly known "imaginary number": "i" ; which represents the "imaginary number" ; " √-1 " .
Since: "i = √-1" ;
Note that: " i² = (√-1)² = √-1 * √-1 = √(-1*-1) = √1 = 1 .
__________________________________________________
