Ok what is the question lol
        
                    
             
        
        
        
Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters. 
First of all, we will find z-scores for data points using z-score formula.
 , where,
, where,
z = z-score,
x = Sample score,
 = Mean,
 = Mean,
 = Standard deviation.
 = Standard deviation.



Let us find z-score of data point 22.03.



Using probability formula  , we will get:
, we will get:

 
  
 
 
Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.
 
        
             
        
        
        
The life expectancies of residents of a country for which the average annual income is $80,000 for the three models are 12309.9352, 172.2436 and 4828.1393
The life expectancies of the models are given as:
 --- model 1
 --- model 1
 --- model 2
 --- model 2
 --- model 3
 --- model 3
Given that the average annual income is $80,000;
We simply substitute 80000 for income in the equations of the three models.
So, we have:
<u>Model 1</u>



<u>Model 2</u>



<u>Model 3</u>



Hence, the life expectancies are 12309.9352, 172.2436 and 4828.1393
Read more about linear models at:
brainly.com/question/8609070