The volume of a cube is V=s^3, so s=V^(1/3).
The area of a cube is A=6s^2, using s found above we have:
A=6(V^(2/3))
Let V and S be the volume and area of the larger and v and s be the volume and area of the smaller cube.
A:a
6(V^(2/3)):6(v^(2/3))
V^(2/3):v^(2/3), we are given that V=216 and v=64 so
216^(2/3):64^(2/3)
36:16
9:4
Answer:
part c
Step-by-step explanation:
because i have done it before
Answer:
y=mx+b is the formula. So -8=-3x+5 would be the answer..
since (x,y) just substitute these numbers you have it into the formulas... Take y from (5,-8) and place it into y=mx+b. Next take the slope which is -3. And then since its a postive number we <em>add</em> are x from (x,y). -8=-3x+5. We also add x next to the slope (-3) becuase we are trying to solve for x. And we <em>always</em> put it next to the slope. Hope this helps!
Plug in 3 for x so
2(3)+2
6+2=
8
The evaluation is 8
Answer:
D: The function has a hole when x = 3, and vertical asymptotes when x = 0 and x = 5.
Step-by-step explanation:
The given rational function has vertical asymptotes and holes. Remember that an asymptote is placed when the function has undetermined results, when we give a x-value and the y-value cannot be determined, there we say exists an asymptotes, which is a punctual line that represents a discontinuation of the graph, the trace cannot cross that asymptote, it divide the whole function graph.
So, in this case we have to undetermined results when the function has a hole of x = 3, and vertical asymptotes when x = 0 and x = 5.
