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3 years ago

Three dice are rolled what is the probability that the total number of spots showing is

Mathematics

1 answer:

Kryger [21]3 years ago

7 0

The probability would be 25 percent

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Solve with work shown. X/3+6 equals -6

8090 [49]

We start out with x/3+6=-6. Subtract 6 from both sides, and you get x/3=-12. Multiply the equation by three and you get x=-36. x=-36 should be your final answer.

6 0

3 years ago

2/3 – 2/6 write answer as a fraction

lisabon 2012 [21]

Answer:

It's 1/3

Step-by-step explanation:

2/6 is equivalent to 1/3, so you can rewrite the question as 2/3 - 1/3.

5 0

3 years ago

Read 2 more answers

If 13cos theta -5=0 find sin theta +cos theta / sin theta -cos theta

Ivahew [28]

Step-by-step explanation:

We have to find the value of (sinθ + cosθ)/(sinθ - cosθ), when 13 cosθ - 5 = 0.

$\red{\frak{Given}} \begin{cases} & \sf {13\ cos \theta\ -\ 5\ =\ 0\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \big\lgroup Can\ also\ be\ written\ as \big\rgroup} \\ & \sf {cos \theta\ =\ {\footnotesize{\dfrac{5}{13}}}} \end{cases}$

Here, we're asked to find out the value of (sinθ + cosθ)/(sinθ - cosθ), when 13 cosθ - 5 = 0. In order to find the solution we're gonna use trigonometric ratios to find the value of sinθ and cosθ. Let us consider, a right angled triangle, say PQR.

Where,

PQ = Opposite side
QR = Adjacent side
RP = Hypotenuse
∠Q = 90°
∠C = θ

As we know that, 13 cosθ - 5 = 0 which is stated in the question. So, it can also be written as cosθ = 5/13. As per the cosine ratio, we know that,

$\rightarrow {\underline{\boxed{\red{\sf{cos \theta\ =\ \dfrac{Adjacent\ side}{Hypotenuse}}}}}}$

Since, we know that,

cosθ = 5/13
QR (Adjacent side) = 5
RP (Hypotenuse) = 13

So, we will find the PQ (Opposite side) in order to estimate the value of sinθ. So, by using the Pythagoras Theorem, we will find the PQ.

Therefore,

$\red \bigstar {\underline{\underline{\pmb{\sf{According\ to\ Question:-}}}}}$

$\rule{200}{3}$

$\sf \dashrightarrow {(PQ)^2\ +\ (QR)^2\ =\ (RP)^2} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ +\ (5)^2\ =\ (13)^2} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ +\ 25\ =\ 169} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ =\ 169\ -\ 25} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ =\ 144} \\ \\ \\ \sf \dashrightarrow {PQ\ =\ \sqrt{144}} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{PQ\ (Opposite\ side)\ =\ 12}}}}_{\sf \blue{\tiny{Required\ value}}}}$

∴ Hence, the value of PQ (Opposite side) is 12. Now, in order to determine it's value, we will use the sine ratio.

$\rightarrow {\underline{\boxed{\red{\sf{sin \theta\ =\ \dfrac{Opposite\ side}{Hypotenuse}}}}}}$

Where,

Opposite side = 12
Hypotenuse = 13

Therefore,

$\sf \rightarrow {sin \theta\ =\ \dfrac{12}{13}}$

Now, we have the values of sinθ and cosθ, that are 12/13 and 5/13 respectively. Now, finally we will find out the value of the following.

$\rightarrow {\underline{\boxed{\red{\sf{\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}}}}}}$

By substituting the values, we get,

$\rule{200}{3}$

$\sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ {\footnotesize{\dfrac{\Big( \dfrac{12}{13}\ +\ \dfrac{5}{13} \Big)}{\Big( \dfrac{12}{13}\ -\ \dfrac{5}{13} \Big)}}}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ {\footnotesize{\dfrac{\dfrac{17}{13}}{\dfrac{7}{13}}}}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{13} \times \dfrac{13}{7}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{\cancel{13}} \times \dfrac{\cancel{13}}{7}} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{7}}}}}_{\sf \blue{\tiny{Required\ value}}}}$

∴ Hence, the required answer is 17/7.

6 0

2 years ago

She worked a total of 15 hours. If she makes $15 per hour tutoring and $9 per hour at the grocery store and made a total of $159

Ugo [173]

Answer:

11 hours she worked at the grocery store

Step-by-step explanation:

assuming,

the number of hours worked at tutoring = x

the number of hours worked at grocery store = y

which means,

the amount she made at tutoring = x* $15

the amount she made at grocery store = y*$9

we have 2 equations

total number of hours

1) x+y= 15

total amount she earned

2) x* $15+ y* $9= $159

From equation 1

x+y= 15

x=15-y

we replace this x value in equation 2

x* $15+ y* $9= $159

(15-y)* $15+ y* $9= $159

(15*15)- 15y+9y=159

225-6y=159

225-159=6y

66=6y

66/6=y

11=y the number of hours she worked at grocery store.

we place y=11 in our derived x equation

x=15-y

x=15-11

x=4 the number of hours she worked at tutoring.

3 0

3 years ago

If the parallel sides of a trapezoid are contained by the lines and , find the equation of the line that contains the midsegment

Fittoniya [83]

Answer:

Equation of midsegment line: y = (-1/4)x + 2.

Step-by-step explanation:

If the parallel sides of a trapezoid are contained by the lines:-

y = (-1/4)x +5 and y = (-1/4)x - 1

Midsegment of any trapezoid is the line segment

1. that is parallel to pair of parallel side of trapezoid and

2. that passes through the middle of the trapezoid and cuts the other two sides into equal-half.

It means the midsegment would have same slope as the parallel lines and y-intercept would be in the middle of intercepts of parallel lines.

So y = mx + b

where m = -1/4 and b = (5 - 1)/2 = 4/2 = 2.

Hence, the equation of midsegment would be y = (-1/4)x + 2.

6 0

3 years ago