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shepuryov [24]
3 years ago
15

If the parallel sides of a trapezoid are contained by the lines and , find the equation of the line that contains the midsegment

. Show equations and all work that leads to your answer.

Mathematics
1 answer:
Fittoniya [83]3 years ago
6 0

Answer:

Equation of midsegment line: y = (-1/4)x + 2.

Step-by-step explanation:

If the parallel sides of a trapezoid are contained by the lines:-

y = (-1/4)x +5 and y = (-1/4)x - 1

Midsegment of any trapezoid is the line segment

1. that is parallel to pair of parallel side of trapezoid and

2. that passes through the middle of the trapezoid and cuts the other two sides into equal-half.

It means the midsegment would have same slope as the parallel lines and y-intercept would be in the middle of intercepts of parallel lines.

So y = mx + b

where m = -1/4 and b = (5 - 1)/2 = 4/2 = 2.

Hence, the equation of midsegment would be y = (-1/4)x + 2.

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Use PEMDAS

"Evaluate the expression" just means solve until you can't simplify anymore. You must solve it in a certain order according to PEMDAS: Parentheses, Exponents, Multiply, Divide, Add, Subtract.

What does the beginning of the expression look like? It is (-8)^{2}.

According to PEMDAS, you must solve what is in the parentheses *first*. But, since there is only a number (-8), there is nothing to solve for and you can move on to exponents.

The squared symbol, the little 2, means you have to square what is *inside* the parentheses. (-8)^{2} = 64, because -8 times itself is 64.

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