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3 years ago

The mass of 4 large zucchini is about 2 kilograms. About how many grams will 1 large zucchini have?

1 answer:

3 0

To solve this problem you must apply the proccedure shown below:

1. You have the following information given in the problem:

-The mass of 4 large zucchini is about 2 kilograms.

2. Then, you have:

1 kilogram-----1000 grams
2 kilograms--..x

x=2x1000/1
x=2000 grams

3. Then, you have:

4 large zucchini----2000 grams
1 large zucchini----x

x=2000/4
x=500 grams

The answer is: 500 grams

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NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions

Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector $\vec{v}$ in some vector space $\mathbb R^n$ we have

$\vec{v} = \langle a,b\rangle$

This is the component form. I don't like that way. It is probably used in high school, but

$\vec{v} = \begin{pmatrix} a\\ b\\ \end{pmatrix}$

is preferable because the inner product on $\mathbb R^n$ is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as $\vec{v} = 2i+2j$

For this question, I think you meant

vectors

$\vec{u_1} = (-8, 12)$

$\vec{u_2} = (13, 15)$

Once

$\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}$

Considering that the dot product is

$\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76$

and the norm of $\vec{u_1}$ is $||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}$

and the norm of $\vec{u_2}$ is $||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}$

Thus,

$\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}$

$\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)$

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2 years ago

Which y values are represented on the graph below?

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3 years ago

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sveticcg [70]

We want to check how many intersections line A and B have, that is, we want to check how many common solutions do these equations have:

i) 2x + 2y = 8

ii) x + y = 4

use equation ii) to write y in terms of x as : y=4-x,

substitute y =4-x in equation i):

2x + 2y = 8
2x + 2(4-x) = 8
2x+8-2x=8
8=8

this is always true, which means the equations have infinitely many common solutions.

Answer: There are infinitely many solutions.

4 0

3 years ago

Help me! :( will appreciate any type of help

KengaRu [80]

Answer:32

Step-by-step explanation: (2+3x)= 98 then solve

8 0

2 years ago

Find two consecutive even integers whose sum is 30

Yuliya22 [10]

Answer:

14 & 16

Step-by-step explanation:

30÷2=15

15+15=30, so we can make the conclusion...

14+16=30

3 0

2 years ago