Y=x-1 as the general line equation is y=x
Y=kx
when y=56, x=7
56=7k
k=8
when x=4
y=8(4)
y=32
value of y=32
8*0=0 and 8+0=8
the answer is 8 and 0
It appears that you have a derivative and want to integrate...
dy/dx=1+3√x
y(x)=x+(2/3)x^(3/2)+C you are given that f(4)=25 so we can solve for the constant of integration...
y(4)=25=4+16/3+C
21=16/3+C
(63-16)/3=C
47/3=C so
f(x)=x+(2/3)x^(3/2)+47/3
f(x)=(3x+2x^(3/2)+47)/3
