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Pie
2 years ago
12

What is the equation?

Mathematics
1 answer:
Nana76 [90]2 years ago
8 0

Answer:

y=-2+4

Step-by-step explanation:

we know the y intercept is four, so we can plug that into y=mx+b

so far we know y=mx+4

and the equation for finding slope is \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

so let's find two points on the graph

let's make it easy on ourselves and use the points laid out for us

(0,4) and (2,0)

\frac{0-4}{2-0}

solving that would come out to be \frac{-4}{2}

simplified, that would be -2

now that we know the slope, we can put them into slope-intercept form

y=-2+4

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Answer:

<em>hello your question lacks some information attached below is the complete question</em>

answer : NO

Step-by-step explanation:

Determine the probability of not selecting an obese subject in 3 trials

= P ( not obese in 3 randomly selected ) = ( 1 - 0.111 )^3

= 0.703

The probability > 0.05

hence it is insignificant therefore the answer is NO

6 0
2 years ago
Boxes of granola are on sale at a price of 2 for $4.50. There are 12 ounces of
Softa [21]

Answer:

4.5/2 which is 2.25

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
A ticket printer made 450 tickets in 9 minutes. Another ticket printer made tickets for 5 minutes at twice the rate of the first
OlgaM077 [116]

Answer:

500

Step-by-step explanation:

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8 0
2 years ago
Show work please.<br><br> solve system of equations using matrices.
nadya68 [22]

Answer:

(t, t -1, t)

Step-by-step explanation:

You have three unknowns but only 2 equations, so you can't really SOLVE this...you can get a solution with a variable still in it (I forget what this is called.  I think it refers to infinite many solutions).  Here's how it works:

Set up your matrix:

\left[\begin{array}{ccc}1&-2&1\\2&-1&-1\\\end{array}\right] \left[\begin{array}{ccc}2\\1\\\end{array}\right]

You want to change the number in position 21 (the 2 in the scond row) to a 0 so you have y and z left.  Do this by multiplying the top row by -2 then adding it to the second row to get that 2 to become a 0.  Multiplying in a -2 to the top row gives you:

\left[\begin{array}{ccc}-2&4&-2\\2&-1&-1\\\end{array}\right]\left[\begin{array}{ccc}-4\\1\\\end{array}\right]

Then add, keeping the first row the same and changing the second to reflect the addition:

\left[\begin{array}{ccc}-2&4&-2\\0&3&-3\\\end{array}\right] \left[\begin{array}{ccc}-4\\-3\\\end{array}\right]

The second equation is this now:

3y - 3z = -3.  Solving for y gives you y = z - 1.  Let's let z = t (some random real number that will make the system true.  Any number will work.  I'll show you at the end.  Just bear with me...)

lf z = t, and if y = z - 1, then y = t - 1.  So far we have that y = t - 1 and z = t.  Now we solve for x:

From the first equation in the original system,

x - 2y + z = 2.  Subbing in t - 1 for y and t for z:

x - 2(t - 1) + t = 2.  Simplify to get

x - 2t + 2 + t = 2  and  x - t = 0, and x = t.  So the solution set is (t, t - 1, t).  Picking a random value for t of, let's say 2, sub that in and make sure it works.  If:

x - 2y + z = 2, then t - 2(t - 1) + t = 2 becomes t - 2t + 2 + t = 2, and with t = 2, 2 - 2(2) + 2 + 2 = 2.    Check it:  2 - 4 + 4 = 2 and 2 = 2.  You could pick any value for t and it will work.

6 0
2 years ago
I need help with this 8
zubka84 [21]

The complete proof for the given parallelogram is given in the image attached below.

<h3>What is a Parallelogram?</h3>

A parallelogram is a quadrilateral whose opposite sides are parallel and also congruent to each other.

The complete proof would be as shown below:

1. ABCD is a parallelogram [given]

2. AB║CD [Definition of parallelogram]

3. ∠1 ≅ ∠2, ∠3 ≅ ∠4 [alternate interior angles theorem]

4. AB ≅ CD [Definition of parallelogram]

5.  ΔABE ≅ ΔCDE [ASA]

6. AE ≅ CE, BE ≅ DE [CPCTC]

7. AC and BD bisects each other at E [definition of segment bisector]

Learn more about parallelogram on:

brainly.com/question/3050890

#SPJ1

6 0
1 year ago
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