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NeTakaya
3 years ago
5

Find the missing side. PLEASE HELP FAST !

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
5 0

Answer:

It is 28.5m. Hope this helps!! Have a good day..

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The equation 2x^2 + x - 1 = 0 has two solutions. Find an equation of the form ax^2 + bx + c = 0, which solutions....
leonid [27]

Answer:

Step-by-step explanation:

Let the solution to

2x^2 + x -1 =0

x^2+ (1/2)x -(1/2)

are a and b

Hence a + b = -(1/2) ( minus the coefficient of x )

ab = -1/2 (the constant)

A. We want to have an equation where the roots are a +5 and b+5.

Therefore the sum of the roots is (a+5) + (b+5) = a+ b +10 =(-1/2) + 10 =19/2.

The product is (a+5)(b+5) =ab + 5(a+b) + 25 = (-1/2) + 5(-1/2) + 25 = 22.

So the equation is

x^2-(19/2)x + 22 =0

2x^2-19x + 44 =0

B. We want the roots to be 3a and 3b.

Hence (3a) + (3b) = 3(a+b) = 3(-1/2) =-3/2 and

(3a)(3b) = 9(ab) =9(-1/2)=-9/2.

So the equation is

x^2 +(3/2) x -9/2 = 0

2x^2 + 3x -9 =0.

4 0
3 years ago
Find c and round to the nearest tenth. thank you in advance
PSYCHO15rus [73]

Answer and Step-by-step explanation:

90ft = a

55ft = b

50ft = c

Plug into equation.

50^{2}  = 90^{2}  + 55^{2}  - 2(90)(55)cosC\\\\2500 = 11125 - 9900(cosC)\\\\-8625 = -9900(cosC)\\\\0.8712 = cosC\\\\cos^{-1} (0.8712) = C\\\\29.4

29.4° is the answer.

4 0
3 years ago
The graph of f ′ (x), the derivative of f of x, is continuous for all x and consists of five line segments as shown below. Given
Rom4ik [11]

f'(x)\ge0 for all x in [-3, 0], so f(x) is non-decreasing over this interval, and in particular we know right away that its minimum value must occur at x=-3.

From the plot, it's clear that on [-3, 0] we have f'(x)=-x. So

f(x)=\displaystyle\int(-x)\,\mathrm dx=-\dfrac{x^2}2+C

for some constant C. Given that f(0)=7, we find that

7=-\dfrac{0^2}2+C\implies C=7

so that on [-3, 0] we have

f(x)=-\dfrac{x^2}2+7

and

f(-3)=\dfrac52=2.5

5 0
3 years ago
Someone please help me will give BRAILIEST!!!!!!
asambeis [7]
The answer to this problem is  2/5
6 0
2 years ago
Read 2 more answers
the point-slope form of the question of the line that passes through (-4,-3) and (12,1) is y-1=1/4(x-12). what is the standard f
Alexeev081 [22]
Well first off you multiply the parenthesis 1/4(x-12) you get -1=1/4x-3 then you subtract the one so now the y can be by itself the you get Y=1/4x-2
5 0
3 years ago
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