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vovangra [49]
3 years ago
7

Simplify (4.4 × 10^17) + (3.3 × 10^14)

Mathematics
2 answers:
UkoKoshka [18]3 years ago
5 0

Answer:

4.40033 x 10^17

Step-by-step explanation:

Serggg [28]3 years ago
5 0

Answer:

=440330000000000060

Step-by-step explanation:

4.4(1017)+3.3(1014)

=(4.4)(100000000000000000)+3.3(1014)

=440000000000000060+3.3(1014)

=440000000000000060+(3.3)(100000000000000)

=440000000000000060+330000000000000

=440330000000000060

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andriy [413]
15% are deluxe rooms
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3 years ago
HELP, i’m not good a triangles
seraphim [82]

Answer:

B

Step-by-step explanation:

SSS stand for Side Side Side, so the truangle must identify all it's sides. To identify sides it uses lines through the side like in B where 1 side has 1 line, 1 side has 2 lines, and the other side has 3 lines. That is the side identifiers, and because each side in B matches with 1 side in A, means that A and B are congruent because they have the same sides, so SSS.

This is confusing to explain, if you have any questions post them in the comments.

3 0
2 years ago
A politician estimates that 61% of his constituents will vote for him in the coming election. How many constituents are required
Katyanochek1 [597]

Using the z-distribution, as we are working with a proportion, it is found that 1016 constituents are required.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The estimate is of \pi = 0.61, while the margin of error is of M = 0.03, hence solving for n we find the minimum sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.61(0.39)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.61(0.39)}

\sqrt{n} = \frac{1.96\sqrt{0.61(0.39)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.61(0.39)}}{0.03}\right)^2

n = 1015.5

Rounding up, 1016 constituents are required.

More can be learned about the z-distribution at brainly.com/question/25890103

8 0
1 year ago
Solve the equation for x, where x is a real number (5 points): <br> -11x^2 + 5x - 3 = 0
fenix001 [56]
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
                   x = [ -b ± √(b^2 - 4ac) ] / (2a)
                   x = [ -5 ± √((5)^2 - 4(-11)(-3)) ] / ( 2(-11) )
                   x = [-5 ± √(25 - (132) ) ] / ( -22 )
                   x = [-5 ± √(-107) ] / ( -22)
Since we conclude that √-107 is nonreal, the answer to this question is that there are no real solutions.
7 0
3 years ago
A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the
Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= \pi r^2h

According to the problem,

\pi r^2 h=25

\Rightarrow h=\frac{25}{\pi r^2}

The surface area of the base of the can is = \pi r^2

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× \pi r^2)

The lateral surface area of the can is = 2\pi rh

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× 2\pi rh)

                                                 =\$2.5 \pi r h

Total cost of metal is C= 2.00 \pi r^2+2.5 \pi r h

Putting h=\frac{25}{\pi r^2}

\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}

\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}

Differentiating with respect to r

C'=4\pi r- \frac{62.5}{ r^2}

Again differentiating with respect to r

C''=4\pi + \frac{125}{ r^3}

To find the minimize cost, we set C'=0

4\pi r- \frac{62.5}{ r^2}=0

\Rightarrow 4\pi r=\frac{62.5}{ r^2}

\Rightarrow  r^3=\frac{62.5}{ 4\pi}

⇒r=1.71

Now,

\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0

When r=1.71 cm, the metal cost will be minimum.

Therefore,

h=\frac{25}{\pi\times 1.71^2}

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0
3 years ago
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