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Yuliya22 [10]
3 years ago
13

Help me on question 3

Mathematics
1 answer:
alexira [117]3 years ago
5 0
(X-5)(-6+x) is -6x+x^2+30-5x which is x^2-11x+30 so Dan is correct Emily will have made a mistake when timesong either -6 x XOR -5 x x.
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Enter the number 46.1979 rounded to the nearest hundredth (two decimal places)
muminat

Answer:

It should be 46.20

Step-by-step explanation:

You're rounding to the nearest hundredth. So you have 46.1979 to start out with. Then you count 2 places so you end at the 1st 9. Well, behind the 9 is a 7 so you round up and get 20

6 0
1 year ago
Mike just hopped on the edge of a merry-go-round. What are his linear and angular speeds if the diameter of the merry-go-round i
dsp73

Step-by-step explanation:

Given that,

The diameter of the merry-go-round, d = 14 feet

Time taken, t = 6 seconds

Radius, r = 7 feet

The linear speed of the merry-go-round is given by :

v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 7}{6}\\\\=7.33\ m/s

Also,

v=r\omega

Where

\omega is the angular speed

So,

\omega=\dfrac{v}{r}\\\\\omega=\dfrac{7.33}{7}\\\\=1.04\ rad/s

Hence, his linear and angular speeds are 7.33 m/s and 1.04 rad/s.

8 0
3 years ago
Congruent triangle measures.​
Charra [1.4K]

Answer:

3x=4x-9(By CPCT)

x=9

Therefore,sides are27

5 0
2 years ago
Steps are very much required they should be clear and neat please i need to understand this I'm taking a practice test for my fu
Volgvan

Answer:

2nd option

Step-by-step explanation:

the mean is calculated as

mean = \frac{sum}{count}

         = \frac{4x+5+7x-6-8x+2}{3}

         = \frac{3x+1}{3}

         = \frac{3x}{3} + \frac{1}{3}

        = x + \frac{1}{3}

8 0
2 years ago
An object in a simulation accelerates
notsponge [240]

Observe the graph below. This graph represents the scenario.

The question is ill formated, the complete question is

In a simulation, a moving object accelerates from rest to 4 meters per second in 2 seconds. For the following three seconds, it increases linearly until it reaches a speed of 10 meters per second. Following three seconds at that speed (acceleration = 0), the item progressively decelerates until it comes to rest two seconds later. Draw the graph of this scenario for 10 seconds?

I'll describe how the graph may show.

It will move diagonally upward from time 0 to 2 seconds until it reaches the y axis at a speed of 4 m/s.

Then, from 2 to 5, the position will move up diagonally until it reaches the y axis at a speed of 10 m/s.

The next 5 to 8 seconds will be horizontal.

After that, it will descend diagonally.

Observe the graph below. This graph represents the scenario.

Learn more about Acceleration here-

brainly.com/question/21509870

#SPJ10

5 0
2 years ago
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