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Goshia [24]
3 years ago
12

Cady's cats often share a carton of cat milk. Sammy always drinks 1/3 of the carton, tommy drinks 5/12 of the carton and Suzi dr

inks 1/6 of the carton . What fraction of the carton of cat milk is left over ?
Mathematics
1 answer:
juin [17]3 years ago
4 0
Start by making the denominators equal.

1/3 becomes 4/12
1/6 becomes 2/12
and you have 5/12.

Add together to get 10/12.

Once simplified, the answer should be 5/6.
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Which is equal to 2√2 ? Select all that apply.
mars1129 [50]

Answer:

B and C

Step-by-step explanation:

Sin 45 or Cosine 45.

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3 years ago
Write the equation of the line that includes the point (1,5) and has a slope of 3 in standard form.
Ymorist [56]

Answer:

-3x + y = 2

Step-by-step explanation:

The slope is 3. So the coefficient of x is 3.

when x = 1, y = 5.

So 3*1 + c = 5

So c is 2.

So y = 3x + 2

Therefore, taking 3x to the LHS, we get,

-3x + y = 2

Hope it helps ;)

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3 years ago
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Write the equation of the line perpendicular to 3x+2y=-8 that passes through (3,1). Write you answer in slope-intercept form. Sh
Verdich [7]

Answer:

y = (2/3)x - 1,  slope-intercept form

Step-by-step explanation:

3x + 2y = - 8

2y = -3x - 8

y = (-3/2) x - 4

Slope of this line is -3/2.

For the perpendicular line slope is 2/3.

Point - slope form is

(y - y1) = m(x - x1)

Point is (3,1). Slope m = 2/3.

y - 1 = (2/3)*(x - 3)

y - 1 = (2/3)x - 2

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3 0
3 years ago
Write an equation for the description.A number x increased by 13 is 116​
seropon [69]

Answer:

X+13=116

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
PLEASE SHOW WORK
CaHeK987 [17]

(C)

Step-by-step explanation:

The volume of the conical pile is given by

V = \dfrac{\pi}{3}r^2h

Taking the derivative of V with respect to time, we get

\dfrac{dV}{dt} = \dfrac{\pi}{3}\dfrac{d}{dt}(r^2h)

\:\:\:\:\:\:\:= \dfrac{\pi}{3}\left(2rh\dfrac{dr}{dt} + r^2\dfrac{dh}{dt}\right)

Since r is always equal to h, we can set

\dfrac{dr}{dt} = \dfrac{dh}{dt}

so that our expression for dV/dt becomes

\dfrac{dV}{dt} = \dfrac{\pi}{3}\left(3r^2\dfrac{dh}{dt}\right)

\:\:\:\:\:\:\:= \pi r^2\dfrac{dh}{dt}

Solving for dh/dt, we get

\dfrac{dh}{dt} = \dfrac{1}{\pi r^2}\dfrac{dV}{dt}

\:\:\:\:\:\:\:= \dfrac{1}{9\pi\:\text{m}^2}(36\:\text{m}^3\text{/s})

\:\:\:\:\:\:\:= \dfrac{4}{\pi}\:\text{m/s}

7 0
3 years ago
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